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Veronika [31]
4 years ago
8

Probability ~

Mathematics
1 answer:
tatuchka [14]4 years ago
4 0

A.

A - selecting a milk chocolate

P(A)=1-\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{15}{15}-\dfrac{3}{15}-\dfrac{5}{15}=\dfrac{7}{15}

B.

The number of the chocolates must be a multiple of 15, so there can be 15,30,45,... etc. chocolates in the box.

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Rhonda had $300 to buy supplies for the animal shelter. She bought 8 bags of dog food and 11 leashes. Each bag of food cost $25.
Readme [11.4K]

Answer:

47.33

Step-by-step explanation:

Hey there! I'm happy to help!

We have 8 bags of dog food and each costs $25.19

8(25.19)=201.52

And we have 11 leashes each costing $4.65.

11(4.65)=51.15

We add these totals up.

201.52+51.15=252.67

We subtract this from 300 to see how much is left.

300-252.67=47.33

Rhonda had $47.33 left after her purchases.

Have a wonderful day! :D

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