4 years ago

Probability ~

1 answer:

4 0

A - selecting a milk chocolate

$P(A)=1-\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{15}{15}-\dfrac{3}{15}-\dfrac{5}{15}=\dfrac{7}{15}$

The number of the chocolates must be a multiple of 15, so there can be 15,30,45,... etc. chocolates in the box.

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