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3 years ago

29 more than a number

Mathematics

2 answers:

Georgia [21]3 years ago

4 0

29+x

Hope this helped

vazorg [7]3 years ago

4 0

29+x would be the answer

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with one litre of paint you can paint an area of 8m².how much paint will you need for a wall mural that is 10m wide and 3m high?

Sveta_85 [38]

Answer: 3.75 liters

Step-by-step explanation:

1 liter = 8m^2

area of the wall = l x b (wide x high)

= 10 x 3

= 30m^2

so, quantity of paint needed = 30/8 = 3.75 liters

Hope it helped u,

pls mark as the brainliest -Ayaan707-

^_^

6 0

3 years ago

What is the simplest form of 27/42? a.27/42 d.9/14 b.1 15/27 e.13/21 c.2/3

soldi70 [24.7K]

$\frac{27}{42}=\frac{27:3}{42:3}=\frac{9}{14}\\\\Answer:D$

5 0

3 years ago

Read 2 more answers

the cost per month of one cell phone plan is $30 plus and additional nickel for each text. write an equation that defines the to

storchak [24]

Y= 5c + 30 would be it I believe

7 0

3 years ago

A rectangle, a triangle, and two congruent semicircles were used to form the figure shown. Rectangle 5cm,20cmcircle : radius 5cm

Schach [20]

Answer:

The area of a shape is the amount of space it occupies

Step 1:

We start by calculating the area of the rectangle using:

$\begin{gathered} A_{rectangle}=l\times b \\ \end{gathered}$

By substituting the values, we will have

$\begin{gathered} A_{rectangle}=l\times b \\ A_{rectangle}=20cm\times5cm \\ A_{rectangle}=100cm^2 \\ A_1=100cm^2 \end{gathered}$

Step 2:

we calculate the area of the triangle using:

$A_{triangle}=\frac{1}{2}\times base\times height$

By substituting the values, we will have

$\begin{gathered} A_{tr\imaginaryI angle}=\frac{1}{2}\times base\times he\imaginaryI ght \\ A_{tr\mathrm{i}angle}=\frac{1}{2}\times10cm\times8cm \\ A_{tr\mathrm{i}angle}=\frac{80cm^2}{2} \\ A_{tr\mathrm{i}angle}=40cm^2 \\ A_2=40cm^2 \end{gathered}$

Step 3:

Calculate the area of the two semicircles

$A_{semicircle}=\frac{\pi r^2}{2}$

By substituting the values, we will have

$\begin{gathered} A_{sem\imaginaryI c\imaginaryI rcle}=\frac{\pi r^{2}}{2} \\ A_{sem\mathrm{i}c\mathrm{i}rcle}=3.14\times\frac{5^2}{2} \\ A_{sem\mathrm{i}c\mathrm{i}rcle}=39.25cm^2 \\ Area\text{ of two semicircle will be} \\ A_3=39.25cm^2\times2 \\ A_3=78.5cm^2 \end{gathered}$

Step 4:

Calculate the area of the shape

We will calculate the area of the shape by adding all the individual areas together