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Nimfa-mama [501]

4 years ago

7

A train leaves at 08.43 and arrives at its destination at 09.23. If the train travelled 73 km, what was it's average speed in km

/h? Give your answer rounded to 1 dp.

1 answer:

serg [7]4 years ago

5 0

Answer: 109.5 km/ hr

Step-by-step explanation:

Distance = 73 km

Time = 40 minutes = 40/60 = 2/3 hours

Speed = Distance / time

= 73 / 2/3

= 73 x 3/2 = 219 / 2 = 109.5 km/hr

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7 0

4 years ago

lidiya [134]

Answer:

The area of the rectangle is 4 sq yards.

Step-by-step explanation:

Given that,

The length of the rectangle, $L=\dfrac{2}{13}\ yards$

The breadth of the rectangle, B = 26 yards

We need to find the area of the rectangle. The formula for the area of a rectangle is given by :

A = LB

Put all the values,

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6 0

3 years ago

Suppose that an insurance company classifies people into one of three classes — good risks, average risks, and bad risks. Their

Dominik [7]

Answer: Our required probability is 0.745.

Step-by-step explanation:

Since we have given that

Probability of getting good risks people = 0.05

Probability of getting average risks people = 0.15

Probability of getting bad risks people = 0.30

Probability of getting good risk accident = 0.2

Probability of getting average risk accident = 0.5

Probability of getting bad risk accident = 0.3

So, Probability of people having accident in a year is given by

$0.05\times 0.2+0.15\times 0.5+0.30\times 0.3\\\\=0.175$

Probability of people either good or average risk given that he\she had no accident is given by

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3 0

3 years ago

A simple random sample of 144 observations was taken from a large population. The sample mean and the standard deviation were de

Vera_Pavlovna [14]

Answer:

The standard error of mean = 10

Step-by-step explanation:

Given a simple sample of 144 observations was taken from a large population.

The size of large sample 'n' = 144

Given sample mean and the standard deviation were determined to be 1234 and 120 respectively.

Given standard deviation of sample (S) = 120

The standard error of mean is determined by

$SE (X^{-} ) = \frac{S.D}{\sqrt{n} }$

$SE (X^{-} ) = \frac{120}{\sqrt{144} } = 10$

<u>Final answer</u>:-

The standard error of mean = 10

4 0

3 years ago

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olganol [36]

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3 years ago