Answer:
a. engranaje 1 → engranaje 2 → engranaje 3 → engranaje 4
z1 = 10 z2 = 20 z3 =10 z4 = 20
b. n2 = 600 rpm, n3 = 1200 rpm, n4 = 600 rpm
la relacion de transmision = 2
Explanation:
where z1 = 10, z2 = 20, z3 = 10, z4 = 20
and n1 = 1200 rpm
n2 = n1 * z1/z2 = (1200 * 10)/ 20 = 600 rpm
n3 = n2 * z2/z3 = (600 * 20)/ 10 = 1200 rpm
n4 = n3 * z3/z4 = (1200 * 10)/ 20 = 600 rpm
la relacion de transmision = z2/z1 * z3/z2 * z4/z3
= 20/10 * 10/20 * 20/10 = 2 * 0.5 * 2 = 2
Answer:
D the answer is D or c one of those 2
Answer:
The given statement is False.
Explanation:
- Needs Met Rating of a result show us that how much the result is fulfilling the query of the user. The greater the needs met rating is, the greater the satisfaction of the user is.
- If a page has high quality then it can or can not be useful for the user.
- If the page has high quality as well as high needs met rating then it is best for the user.
- If the page has high quality and has low needs met rating that means it is not relevant to the query so not useful for the user.
- Thus, it is concluded that high quality pages in a task shouldn't all get the same needs met rating rating rather need met rating is dependent upon the relevancy and usefulness of the result to the need and query of the user.
Huh???????................
