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sladkih [1.3K]
3 years ago
11

PLEASE HELP ASAP WILL GIVE BRAINLIEST AB¯¯¯¯¯ has end points at A (0, 5) and B (0, 0) . A transformation is performed on AB¯¯¯¯¯

and the image is A'B'¯¯¯¯¯¯¯ with end points A' (0, 10) and B' (0, 5) .
What transformation was preformed on AB¯¯¯¯¯ ?

translated up 5 units

rotated 180° about point A

rotated 90° about point B

reflected across the line y=5
Mathematics
1 answer:
adell [148]3 years ago
3 0
A is your answer im pretty sure took the test
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Find two positive consecutive integers such that the square of the first added to three times the second is 24
Naddika [18.5K]

Answer:

3 and 5

Step-by-step explanation:

Let the two consecutive odd integers be x and x + 2.

Now,

The given statement is

x^2 + 3 \times (x+2)=24\\x^2 + 3x+6-24 = 0 \\x^2 + 3x-18 = 0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x-3)(x+6)=0\\x=3,-6

Taking x=3.

Hence, two consecutive odd integers are 3 and 5.

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Answer:

160

Step-by-step explanation:

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3 years ago
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A rectangular garden has an area of 24 square meters. The width is 8 meters less than twice the length. Find the dimensions of t
OLEGan [10]

Answer:

Length: 6 m

Width: 4 m

Step-by-step explanation:

Area: 24 m^{2}

Width: 2L - 8 m

Length: ?

Formula: A = W * L

Replace the variables:

24 = (2L - 8) * L

24 = 2L^{2} - 8L

0 = 2L^{2} - 8L - 24

or

2L^{2} - 8L - 24 = 0

Solve; if you don't know how to solve it using this method, let me know. It's the expression Ax^{2} +Bx+C

1. 2 (\frac{(2L^2 - 8L - 24)}{2})

2. \frac{(2L)^2 - 8(2L) - 48}{2}

3. \frac{(2L - 12)(2L + 4)}{2}

4. 2(\frac{(L - 6)(2L + 4)}{2})

5. (L-6) (2L+4)

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L = 6

---------------------------------

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L = -2

Since the length cannot be negative, the only real value is 6.

Area: 24 m^{2}

Width: 2L - 8 m

Length: 6 m

Calculate width:

W = 2L - 8

W = 2(6) - 8

W = 12 - 8

W = 4 m

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