The average daily maximum temperature in Syracuse is 21.85°C, and the average daily minimum temperature is -4.7°C. The average d
1 answer:
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Answer:
option-B
Step-by-step explanation:
We are given
At the start of the year, 15 chameleons were introduced into a zoo
so,
The population of chameleons is expected to grow at a rate of 41.42% every year
so, r=0.4142
and x represents the number of years since the chameleons were introduced into the zoo
now, we can set equation to find total population
and we get
now, we can plug values
Average rate of change between 2 years and 4 years:
we can use formula
now, we can plug values
Average rate of change between 4 years and 6 years:
we can use formula
now, we can plug values
Average rate of change between 6 years and 8 years:
we can use formula
now, we can plug values
now, we will check each options
option-A:
we can see that
So, this is FALSE
option-B:
So, this is TRUE
option-C:
This is FALSE
option-D:
we got
so, this is FALSE
Answer:
(a) 99% confidence interval for the percentage of girls born is [0.804 , 0.896].
(b) Yes, the proportion of girls is significantly different from 0.50.
Step-by-step explanation:
We are given that a clinical trial tests a method designed to increase the probability of conceiving a girl.
In the study 400 babies were born, and 340 of them were girls.
(a) Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;
P.Q. = ~ N(0,1)
where, = sample proportion of girls born =
= 0.85
n = sample of babies = 400
p = population percentage of girls born
<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>
<u>So, 99% confidence interval for the population proportion, p is ;</u>
P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5% level
of significance are -2.58 & 2.58}
P(-2.58 < < 2.58) = 0.99
P( <
<
) = 0.99
P( < p <
) = 0.99
<u>99% confidence interval for p</u> = [ ,
]
= [ ,
]
= [0.804 , 0.896]
Therefore, 99% confidence interval for the percentage of girls born is [0.804 , 0.896].
(b) <em>Let p = population proportion of girls born.</em>
So, Null Hypothesis, : p = 0.50 {means that the proportion of girls is equal to 0.50}
Alternate Hypothesis, : p
0.50 {means that the proportion of girls is significantly different from 0.50}
The test statistics that will be used here is <u>One-sample z proportion test</u> <u>statistics</u>;
T.S. = ~ N(0,1)
where, = sample proportion of girls born =
= 0.85
n = sample of babies = 400
So, <u><em>the test statistics</em></u> =
= 19.604
Now, at 0.01 significance level, the z table gives critical value of 2.3263 for right tailed test. Since our test statistics is way more than the critical value of z as 19.604 > 2.3263, so we have sufficient evidence to reject our null hypothesis due to which <u>we reject our null hypothesis</u>.
Therefore, we conclude that the proportion of girls is significantly different from 0.50.
Answer:
I think this is right 50 but I don't know I am 3rd grade
Step-by-step explanation:
<h2>so tha