The return trip took 1 hour 42 minutes longer
Further explanation:
The distance will remain same on return.
The formula for speed is given by:

Let d be the distance
s1 be the speed while going and s2 be the speed while returning
and
t1 be the time while going and t2 be the time while returning
d=500 miles
s1=60 miles per hour
s2=50 miles per hour
We have to calculate time for both trips,
So,
<u>Time while Going:</u>
<u>
</u>
<u>Putting the values of d and s1</u>
<u>
</u>
<u>Converting 8.3</u>
8 will be the hours,
for 0.3 hour
0.3*60=18 minutes
The first trip took 8 hours and 18 minutes.
<u>Time while returning:</u>

Putting the values of d and s1

The difference of both times is: 1 hour 42 minutes
So,
The return trip took 1 hour 42 minutes longer
Keywords: Time, Distance, Speed
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Answer:
can u give more information about the problem, like what are the options?
Step-by-step explanation:
Answer:
-30 ÷ 6= -5
-6 × 5 = -30
-30 ÷ -5 = 6
Step-by-step explanation:
Answer:
x=8
Step-by-step explanation:
subtract 9 from 17 to get x alone on one side. 17-9=x+9-9. That will equal 8=x. Hope this helps
Answer:
m
Step-by-step explanation: