Answer:
It will take 6 hours for the new pump to drain the pool.
Step-by-step explanation:
As the complete question is not given, the complete question is found online and is attached herewith
Let the rate of new pump is given as x=W/t_1
Let the rate of the old pump is given as y=W/t_2
it is given that the time t_2=2t_1
So by substituting the values of t_2 in the rate equation of y
y=W/2t_1
y=(W/t_1*2)=x/2
Also the total rate of both the pumps is given as W/t3 where t3 is given as 4 hours so the equation becomes
x+y=W/4
x+x/2=W/4
3x/2=W/4
As x=W/t_1
3W/2t_1=W/4
Now as W is same on both sides so
3/2t_1=1/4
12=2t_1
t_1=6 hours
So it will take 6 hours for the new pump to drain the pool.
Answer:
5n is your answer hope this help
Answer:
13= -13
14= 57
15= 216
Step-by-step explanation:
hoep this helps
Answer:
31043.09
Step-by-step explanation:
Kinda feel bad for the last person who answered! They were way off but still you need to learn from your mistakes! Welp this answer is STRAIGHT OFF THE BACK from delta MATH! So this IS correct! If this helped click the stars and the heart to help fellow students, educators, etc. Understand this answer is for certain correct! I would add the steps but there is alot!

Multiply 4.8 into (20/3), and multiply 16/9 with (1.2b)

Multiply 9 on both sides
19.2b = 32(9)
19.2b = 288 Divide 19.2 on both sides
b = 15