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3 years ago

I need help with every question I will give brainliest and everything if you do it thannkkkk uuuuu!

Mathematics

1 answer:

konstantin123 [22]3 years ago

6 0

Answer: 1. 144

2. a

3. 790.05

4. 1.5

5. lenght width and height 4/5 = 24

Step-by-step explanation:

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Write the equation of the line that passes through (-2, 6) and (2, 14) in slope- intercept form.

creativ13 [48]

Answer:

Y= 2x+10

Step-by-step explanation:

(-2, 6), (-1, 8), (0, 10), (1, 12), (2, 14)

You add 2 every time

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2 years ago

Find the measure of <1

Dmitry [639]

Consider the triangle (in which angle4 is present)

by angle sum property,

20 + 40 + angle4 = 180

60 + angle4 = 180

angle4 = 180 - 60

angle4 = 120

Also,

angle2 = 120 (vertically opposite angles)

angle1 + angle2 = 180 (linear pair)

angle1 + 120 = 180

angle1 = 180 - 120

angle1 = 60

3 0

3 years ago

Mathematic 18 don’t understand

Dahasolnce [82]

Answer:

8 x 10¹³ is your answers hopes it's helpful to you

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2 years ago

Fernando is 6 feet tall.if 1 inch is approximately 2.54 cm,what is fernandos height in cm.

otez555 [7]

Answer:

182.88cm

Step-by-step explanation:

i looked it up

8 0

3 years ago

Read 2 more answers

A teacher was interested in finding out whether a special study program would increase the scores of students on a national exam

bija089 [108]

Answer:

Check the explanation

Step-by-step explanation:

Going by the first attached image below we reject H_o against H_1 if obs. $T > t_{\alpha /2;n-1}$

here obs.T=1.879

$\therefore obs.T \ngtr 2.447=t_{0.025;6}$

we accept $H_o:\mu _{1}=\mu_{2}$ at 5% level of significance.

i.e there is no sufficient evidence to indicate that the special study program is more effective at 5% level of significance.

this problem is simillar to the previous one except the alternative hypothesis.

Let X_i's denote the bonuses given by female managers and Y_i's denote the bonuses given by male managers.

we assume that $X_i \sim N(\mu _{1},\sigma _{1}^{2}) Y_i \sim N(\mu _{2},\sigma _{2}^{2})$ independently

We want to test $H_0:\mu_{1}=\mu_{2} vs H_1:\mu_{1}\neq \mu_{2}$

define $D_i=X_i-Y_i , i=1(1)8$

now $D_i\sim N(\mu _{1}-\mu _{2}=\mu _{D},\sigma _{1}^{2}+\sigma _{2}^{2}=\sigma _{D}^{2}) , i=1(1)8$

the hypothesis becomes

$H_0:\mu_{D}=0 vs H_1:\mu_{D}\neq 0$

in the third attached image, we use the same test statistic as before

i.e at 5% level of significance there is not enough evidence to indicate a difference in average bonuses .

3 0

3 years ago