Question

Can someone answer this question please?

Answer 1

The solution to the inequality $3x-3\leq -15\,\,or\,\,4x-1\geq 11$ is $x\leq -3\,\,or\,\,x\geq 4$

The number line is shown in figure attached.

Step-by-step explanation:

We need to solve the inequality: $3x-3\leq -15\,\,or\,\,4x-1\geq 11$

Solving the inequality:

$3x-3\leq -15\,\,or\,\,4x-1\geq 11\\Adding\,\,3\,\,on\,\,both\,\,sides\,\,and\,\,1\,\,on\,\,both\,\,sides\\3x-3+3\leq -15+3\,\,or\,\,4x-1+1\geq 11+1\\3x\leq -12\,\,or\,\,4x\geq 12$

Divide by 3 and divide by 12

$x\leq \frac{-12}{3} \,\,or\,\,x\geq \frac{12}{4} \\x\leq -4\,\,or\,\,x\geq 3$

So, value of x can be less than equal to -4 or value of x is greater than equal to 3.

The number line is shown in figure attached.

The solution to the inequality $3x-3\leq -15\,\,or\,\,4x-1\geq 11$ is $x\leq -3\,\,or\,\,x\geq 4$

Keywords: Solving inequalities

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