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3 years ago

What is 9-h divided by 1/8; h = 1/3

Mathematics

1 answer:

Anton [14]3 years ago

8 0

Answer:

160/3

9-1

3=21-1/3*8=160/3

1/8

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Plz help and explain

vovikov84 [41]

To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.

We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.

The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.

Therefore
Area of band
$=(x+10)^2-x^2$ [recall $(a+b)^2=a^2+2ab+b^2$
$=x^2+20x+100-x^2$
$=20x+100$ or 20(x+5) if you wish.

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3 years ago

What is the pattern here?

tigry1 [53]

To get the number at the back, you would need to multiply the number in front by 3 and minus 1.
The answer would be A

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3 years ago

Part A: If (72)x = 1, what is the value of x? Explain your answer. (5 points)

vichka [17]

Answer:

see below

Step-by-step explanation:

Part A: (72)^x = 1

Take the log base 72 of each side

log72(72^x) = log 72(1)

We know log a^b = b log a

x log72(72) = log72(1)

x = log72(1)

x = 0

Part A: (70)^x = 1

Take the log base 70 of each side

log70(70^x) = log70(1)

We know log a^b = b log a

x log70(70) = log70(1)

x = log70(1)

x = 0

7 0

3 years ago

What is the distance between -4 and 7 on a number line?

tiny-mole [99]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Of the 2,598,960 different five-card hands possible from a deck of 52 playing cards, how many would contain all black cards.

kumpel [21]

Answer: 65,780

Step-by-step explanation:

When we select r things from n things , we use combinations and the number of ways to select r things = $^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : The total number of playing cards in a deck = 52

The number of different five-card hands possible from a deck = 2,598,960

In a deck , there are 26 black cards and 26 red cards.

The number of ways to select 5 cards from 26 cards = $^{26}C_{5}=\dfrac{26!}{(26-5)!5!}$

$=\dfrac{26\times25\times24\times23\times22\times21!}{21!(120)}=65780$

Hence, the number of different five-card hands possible from a deck of 52 playing cards such that all are black cards = 65,780

3 0

3 years ago