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strojnjashka [21]
3 years ago
9

How would you replace 27/50 with the nearest half or whole number without using a number line?

Mathematics
1 answer:
irina1246 [14]3 years ago
8 0
25/50 = 1/2 soooooooooooooooooooooooooooooooooo
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Autumn is paying for college in monthly installments. The college requests that a $1000 down payment be made. Autumn will then c
zaharov [31]

a. 500 X 12 =

b. 20,000

3 0
3 years ago
PLEASE SOMEONE HELP ME I NEED HELP WITH THIS QUESTION
skelet666 [1.2K]

Answer:

54%

Step-by-step explanation:

Divide 4943/9014 and multiply by 100 to find percentages.

8 0
2 years ago
How do you solve m+5n=p for m
WITCHER [35]

Answer:

my apologize for dont really understand the question! but this is what i got

m=p-5n or m=-5n+p

8 0
2 years ago
Read 2 more answers
Rita ran 2 km 30 m in a 10 km marathon. How much more distance she has to cover to finish the marathon?
vichka [17]

Answer:

7.970km

Step-by-step explanation:2km 30m=2000m+30m=2030m  (1km=1000m)

total distance is 10km which is 10000m.

10000m Minus 2030m equals 7970m so this give's us the answer of 7.97km (7.970km) Hope this helps!

4 0
2 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
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