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3 years ago

(2xy-7)/3x+8=1 solve for y

1 answer:

4 0

$\frac{2xy - 7}{3x + 8} = 1$
$2xy - 7 = 3x + 8$
$2xy = 3x + 15$
$2xy - 3x = 15$
$x(2y - 3) = 15$
$2y - 3 = \frac{15}{x}$
$2y = 3 + \frac{15}{x}$
$y = 1\frac{1}{2} + \frac{15}{2x}$
$y = \frac{15}{2x} + 1\frac{1}{2}$
$y = 7\frac{1}{2}x^{-1} + 1\frac{1}{2}$

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What it 90000-333÷67778738_22222+555=? My homework tho

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3 years ago

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What is the slope of a line perpendicular to the line whose equation is 2x+8y -64 Fully reduce your answer.

Lelechka [254]

Answer: I am pretty sure it is y=-1/4x-8. Hope this helps!

Step-by-step explanation:subtract the 2x from both sides which gives you 8y=-2x-64. Then you want to divide both sides by 8 to get y=-1/4x-8

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3 years ago

The two-way table shows the distribution of gender to favorite film genre for the senior class at Mt. Rose High School.

Studentka2010 [4]

Answer:

The second statement is correct

Step-by-step explanation:

Hello!

The table shows the information of the favorite film genre of the students of the class regarding their gender.

You have to prove which statement is correct:

1)The probability of randomly selecting a student who has a favorite genre of drama and is also female is about 17 percent.

If you chose a student at random, you need to calculate the probability of its favorite genre being "Drama" (D) and the student being female (F), symbolically: P(D∩F)

To do so you have to divide the number of observed students that are female and like drama by the total number of students:

P(D∩F)= $\frac{24}{240}= \frac{1}{10} =0.10$

This means that the probability of choosing a student at random and it being a female that likes drama is 10%.

This statement is incorrect.

2) Event F for female and event D for drama are independent events.

Two events are independent when the occurrence of one of them doesn't affect the probability of occurrence of the other one.

So if F and D are independent then:

P(F)= P(F|D)

-or-

P(D)=P(D|F)

The probability of the event "Female" is equal to $P(F)= \frac{Total females in the class}{n} = \frac{144}{240} = \frac{3}{5}= 0.6$

The probability of the event "Drama" is:

$P(D)= \frac{Total students that like "Drama"}{n}= \frac{40}{240}= \frac{1}{6}= 0.166$

$P(F|D)= \frac{P(FnD)}{P(D)}= \frac{\frac{1}{10} }{\frac{1}{6} }= \frac{3}{5} = 0.6$

As you can see P(F)= 0.6 and P(F|D)= 0.6 so both events are independent.

This statement is correct.

3) The probability of randomly selecting a male student, given that his favorite genre is horror, is 16/40

This is a conditional probability, you already know that the student likes horror movies (H), and out of that group you want to know the probability of the student being male (M):

$P(M|H)= \frac{number of male students that like horror movies}{total students that like horror movies}= \frac{16}{38}= \frac{8}{19} = 0.42$

This statement is incorrect.

4) Event M for male and event A for action are independent events.

Same as the second statement, if the events "Male" and "Action" are independent then:

P(M)= P(M|A)

-or-

P(A)= P(A|M)

$P(M)= \frac{96}{240}= \frac{2}{5}= 0.4$

$P(A)= \frac{72}{240} =\frac{3}{10}= 0.3$

$P(AnM)= \frac{28}{240}= \frac{7}{60}= 0.11666$

$P(M|A)= \frac{P(MnA)}{P(A)}= \frac{\frac{7}{60} }{\frac{3}{10} } = \frac{7}{18}= 0.3888$

$P(M)= \frac{2}{5}$ and $P(M|A)= \frac{7}{18}$

P(M)≠ P(M|A) the events are not independent.

This statement is incorrect.

I hope this helps!

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3 years ago

What is the greatest number of intersection points four coplanar lines can have?

soldi70 [24.7K]

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4 years ago

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blsea [12.9K]

Answer:

a) t(n) = 8n -23

b) t(n) = 7n +24

c) t(n) = -30n +9

d) t(n) = 1.8n +7

Step-by-step explanation:

The general equation for the n-th term of an arithmetic sequence is ...

an = a1 +d(n -1)

Expanding this, we find ....

an = a1 +d·n -d = d·n +(a1 -d)

Comparing that to the form ...

an = m·n +b

we see that ...

m = d

b = (a1 -d)

If you're given a term other than a1, say ak, then you have ...

ak = d·k +(a1 -d)

(a1 -d) = ak -d·k

For a given term and common difference, we can write the desired equation as ...

t(n) = d·n +(ak -d·k) . . . . . . given t(k) = ak and d

Once again, it is convenient to use a spreadsheet to do the calculations for a number of different instances of this problem.

a) t(n) = 8n -23

b) t(n) = 7n +24

c) t(n) = -30n +9

d) t(n) = 1.8n +7

5 0

3 years ago