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3 years ago

(2xy-7)/3x+8=1 solve for y

1 answer:

4 0

$\frac{2xy - 7}{3x + 8} = 1$
$2xy - 7 = 3x + 8$
$2xy = 3x + 15$
$2xy - 3x = 15$
$x(2y - 3) = 15$
$2y - 3 = \frac{15}{x}$
$2y = 3 + \frac{15}{x}$
$y = 1\frac{1}{2} + \frac{15}{2x}$
$y = \frac{15}{2x} + 1\frac{1}{2}$
$y = 7\frac{1}{2}x^{-1} + 1\frac{1}{2}$

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Step-by-step explanation:

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Putting values in the quadratic formula

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