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Svet_ta [14]
3 years ago
8

A publisher reports that 45% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is

actually different from the reported percentage. A random sample of 370 found that 40% of the readers owned a laptop. determine the p-value of the test statistic
Mathematics
1 answer:
nexus9112 [7]3 years ago
8 0

Answer:

z=\frac{0.40 -0.45}{\sqrt{\frac{0.45(1-0.45)}{370}}}=-1.933  

p_v =2*P(z  

Step-by-step explanation:

Information given

n=370 represent the sample selected

\hat p=0.4 estimated proportion of  readers owned a laptop

p_o=0.45 is the value that we want to test

z would represent the statistic

p_v represent the p value

Creating the hypothesis

We need to conduct a hypothesis in order to test if the true proportion of readers owned a laptop is different from 0.45, the system of hypothesis are:  

Null hypothesis:p=0.45  

Alternative hypothesis:p \neq 0.45  

The statistic is:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.40 -0.45}{\sqrt{\frac{0.45(1-0.45)}{370}}}=-1.933  

Calculating the p value  

We have a bilateral test so then the p value would be:

p_v =2*P(z  

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Answer:

i. x^{2} + 26x + 144 - 299 = 0

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Step-by-step explanation:

The area of the figure = 299 cm²

The figure has a shape of a rectangle, so that;

Area of rectangle = length x width

length of the figure = 18 + x

width of the figure = 8 + x

Area of the figure = (18 + x) x (8 + x)

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299 = x^{2} + 26x + 144

x^{2} + 26x + 144 - 299 = 0

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applying the trigonometric formula;

x = (-b ± \sqrt{b^{2} - 4ac}) ÷ 2a

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= (-26 ± \sqrt{676 +620}) ÷ 2

= (-26 ± \sqrt{1296}) ÷ 2

= (-26 ± 36) ÷ 2

x = (-26 + 36) ÷ 2  OR x = (-26 -36) ÷ 2

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Thus, x = 5

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