Answer:
13
Step-by-step explanation:
i got it wrong but this was the correct answer
Answer:
This is really simple, here i'll explain:
Step-by-step explanation:
41.2 x 1.5=
count how many spaces are after the decimal point.
for example, 41.2 has 1 space after the decimal point. The decimal 1.5 also has 1 space after the decimal point. So if you add the spaces it would be 2 because 1 + 1 = 2
After that, take away the decimal point, and just multiply like you normally would.
412 times 15
this would be 6180
after you do the multiplication, you will add the decimal point.
The decimal point will go in between 1 and 8 because there were 2 spaces after the decimal point in the numbers, and if you add them it would be 2 spaces.
Hope this helps!
Answer:
You have a jug holding 6 liters of water. Water from the jug is to be poured into small water bottles which can hold 1/3 liters of water each. How many bottles can you fill with this water?
Step-by-step explanation:
Total quantity of water available = 6 liters
Water that can be filled in each bottle =
liter
Since one bottle can hold
liter, in order to find how many bottles can hold 6 liters, we need to divided 6 by
.
So,
Total number of water bottles that can be filled are = ![\frac{6}{\frac{1}{3} }=6 \times 3 = 18](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%3D6%20%5Ctimes%203%20%3D%2018)
Therefore, we can fill 18 water bottles using the water from the jug.
Answer:
The total volume of the water in the tank after 20 minutes = 1220 gallons
Step-by-step explanation:
Rate of water pumped into the tank r (t) = 30 (1 -
)
Initial volume of water in the tank = 800 gallons
The water in the tank after 20 minutes = Initial volume of water in the tank + Volume of water being pumped in the tank
![V_{total} = V_{i} + V_{pump}](https://tex.z-dn.net/?f=V_%7Btotal%7D%20%3D%20V_%7Bi%7D%20%2B%20V_%7Bpump%7D)
= ![\int\limits^a_b {r(t)} \, dt](https://tex.z-dn.net/?f=%5Cint%5Climits%5Ea_b%20%7Br%28t%29%7D%20%5C%2C%20dt)
Where a = 0 , b = 20
Put the value of r (t) in above equation we get
= ![\int\limits^a_b {30 (1 - e^{-0.16t} )} \, dt](https://tex.z-dn.net/?f=%5Cint%5Climits%5Ea_b%20%7B30%20%281%20-%20e%5E%7B-0.16t%7D%20%29%7D%20%5C%2C%20dt)
= ![30 [ t + \frac{e^{-0.16t} }{0.16} ]](https://tex.z-dn.net/?f=30%20%5B%20t%20%2B%20%5Cfrac%7Be%5E%7B-0.16t%7D%20%7D%7B0.16%7D%20%5D)
= ![30[ (20- 0) + \frac{1}{0.16}(e^{-0.16 (20)}- e^{0} )](https://tex.z-dn.net/?f=30%5B%20%2820-%200%29%20%2B%20%5Cfrac%7B1%7D%7B0.16%7D%28e%5E%7B-0.16%20%2820%29%7D-%20e%5E%7B0%7D%20%20%29)
= 420 gallon
Now, total volume in the tank
![V_{total} = V_{i} + V_{pump}](https://tex.z-dn.net/?f=V_%7Btotal%7D%20%3D%20V_%7Bi%7D%20%2B%20V_%7Bpump%7D)
![V_{total} = 800 + 420](https://tex.z-dn.net/?f=V_%7Btotal%7D%20%3D%20800%20%2B%20420)
![V_{total} = 1220 \ gallon](https://tex.z-dn.net/?f=V_%7Btotal%7D%20%3D%201220%20%5C%20gallon)
Therefore the total volume of the water in the tank after 20 minutes = 1220 gallons