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3 years ago

6

Isabella is playing a board game. The probability that Isabella will lose a turn on her next turn is 11%. Which word or phrase d

escribes the probability that Isabella will lose a turn?

1 answer:

anzhelika [568]3 years ago

6 0

Answer:

unlikely

Step-by-step explanation:

11% is closer to 0 than it is to 1/2. when something may occur, but significantly less than half of the time, we say it is unlikely

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Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.

elena55 [62]

Answer:

$b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

Step-by-step explanation:

Given

$f(b) = b^2 - 75$

Required

Determine the roots

To get the root of the function, then f(b) must be 0;

i.e. f(b) = 0

So, the expression becomes

$0 = b^2 - 75$

Add 75 to both sides

$75 + 0 = b^2 - 75 + 75$

$75 = b^2$

Take square roots of both sides

$\sqrt{75} = \sqrt{b^2}$

$\sqrt{75} = b$

Reorder

$b = \sqrt{75}$

Expand 75 as a product of 25 and 3

$b = \sqrt{25*3}$

Split the expression

$b = \sqrt{25} *\sqrt{3}$

$b = \±5 *\sqrt{3}$

$b = \±5 \sqrt{3}$

$b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

The options are not clear enough; however the roots of the equation are $b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

4 0

3 years ago

If the expression is expanded, what is the coefficient of x?

Nana76 [90]

Answer:

Coefficient is equal to 12

5 0

3 years ago

Write a expression to express k less than double 3.5. THANKS

Arada [10]

k<2(3.5) or simplified k<7

6 0

3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago

Rewrite 6/4 as a percent

emmainna [20.7K]

Hey there!

$\left[\begin{array}{ccc}\boxed{\boxed{ \frac{6}{4}}} \end{array}\right] = \left[\begin{array}{ccc}\boxed{\boxed{150}}\end{array}\right]$

All I did was to multiply each side by 100 which then go me this!

Hope this helps!

5 0

3 years ago

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