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Hoochie [10]
3 years ago
6

Could someone help me with this please and thank you!! Will mark and star!!

Mathematics
1 answer:
timurjin [86]3 years ago
8 0
The rule for expressing a radical as a rational exponent is as follows:
\sqrt[n]{x^y} = x^ \frac{y}{n}
So, to find \sqrt[3]{27x^2y^3z^4} use that rule.
The cube root of 27 is 3, so the equation will start with 3.
3x^ \frac{2}{3} yz^ \frac{4}{3}
Hope that helps!
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