Question

Could someone help me with this please and thank you!! Will mark and star!!

Answer 1

The rule for expressing a radical as a rational exponent is as follows:
$\sqrt[n]{x^y} = x^ \frac{y}{n}$
So, to find $\sqrt[3]{27x^2y^3z^4}$ use that rule.
The cube root of 27 is 3, so the equation will start with 3.
$3x^ \frac{2}{3} yz^ \frac{4}{3}$
Hope that helps!