Answer:
Okay, there are many ways to find if a triangle is congruent.
Let's start with some different terminology.
For the sake of simplicity let us say that S stands for when a side is congruent for both triangles and A stands for when an angle (<) is congruent between both the triangles as well.
So, you need to memorize some rules. If you find that 2 triangles are congruent in the sense of; SSS, SAS, AAS, SAA, and ASA. One thing to remember is that Angle Side Side isn't congruent and is called <em>Donkey Theorem</em>. This theorem only works for right triangles.
One way to know if your triangle isn't congruent is if you can find a part of the triangle that is different.
I know that wasn't the best explanation but I hope it helped anyhow. :)
I’m hanks I need to see the rectangle for this
Answer:
No solution
Step-by-step explanation:
16 < 22 - 8 = 22
16 < 14 = 22
This question doesnt make sense, not only is the inequality false, but the equation isn't equal either.
Answer:
The roots are real and distinct.
Step-by-step explanation:
Given the following equation:
![x^{2} + kx - k -2 =0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%20kx%20-%20k%20-2%20%3D0)
In this problem, a = 1, b = k and c = -k - 2
The discriminant is b² - 4ac, and for the roots to be real and distinct, it must be at least or greater than 0.
We get,
(k)²- 4(1)(-k - 2) = 1 - 4(-k - 2)
= k² + 4k + 8
Let's check:
At k = -2,
![(-2)^{2} + 4(-2) + 8 = 4 - 8 + 8 = 4 ](https://tex.z-dn.net/?f=%28-2%29%5E%7B2%7D%20%2B%204%28-2%29%20%2B%208%20%3D%204%20-%208%20%2B%208%20%3D%204%0A%0A%0A)
At k = 0,
![(0)^2 + 4(0) + 8 = 8](https://tex.z-dn.net/?f=%280%29%5E2%20%2B%204%280%29%20%2B%208%20%3D%208%20)
At k = -100,
![(-100)^2 + 4(-100) + 8 = 10,000 - 400 + 8 = 9608](https://tex.z-dn.net/?f=%28-100%29%5E2%20%2B%204%28-100%29%20%2B%208%20%3D%2010%2C000%20-%20400%20%2B%208%20%3D%209608)
Therefore, we can conclude that for all values of k, the roots are real and distinct.
This has been a long way in answering this question, so it would be great if you could mark me as brainliest
Th square root of 25 is, 5