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Archy [21]
3 years ago
7

Give me the answer fast now now please thank

Mathematics
2 answers:
Zolol [24]3 years ago
8 0

Answer:

#4

Step-by-step explanation:

EDI/HDE

hope it helps

aksik [14]3 years ago
6 0

Answer:

2 should be the answer.

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The graph of f(x) = 24x^2 + 63x +34/ 4x + 3 has an oblique asymptote at y =
g100num [7]

<em>Correct answer is C). 6X+11</em>

Step-by-step explanation:

The given function f(x)= \frac{24x^{2} +63x + 34 }{4x+3}

On simplying the function f(x),

f(x)= \frac{6x(4x+3) -18x +63x + 34 }{4x+3}

f(x)= \frac{6x(4x+3) +45x + 34}{4x+3}

f(x)= \frac{6x(4x+3) +11(4x+3)+x-33 + 34 }{4x+3}

f(x)= \frac{6x(4x+3) +11(4x+3)+x+1}{4x+3}

f(x)=(6x+11)+\frac{(x+1)}{4x+3}

From above equation

"(6x+11)" is Oblique asymptote and \frac{(x+1)}{4x+3} is vertical asymptote

Therefore, Correct answer is C). 6X+11

8 0
3 years ago
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Diego has 90 song on his playlist If 40% of them are hip-hop how many songs Are hip-hop
abruzzese [7]

Answer:

225

Step-by-step explanation:

i used a calculater and did 90 divided by .40

8 0
3 years ago
Finding the Relationship between Two Quantities
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Next time do you mind sending it in a phot because this is a lot of information
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the walls of square storage room in a warehouse are 300 feet long what is the distance from one corner to the other corner of th
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Tou have to 600 divided by 12 is 50 feet
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A police cruiser is traveling at 20.0 m/s when the officer spies a speeder. The cruiser accelerates at 3.0 m/s^2 for 5.0 seconds
Tema [17]

For the first 5.0 seconds, the cruiser covers a distance of

\left(20.0\dfrac{\rm m}{\rm s}\right)(5.0\,\mathrm s)+\dfrac12\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)^2=137.5\,\mathrm m

At this point, the cruiser will have achieved a velocity of

\left(20.0\dfrac{\rm m}{\rm s}\right)+\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)=35\dfrac{\rm m}{\rm s}

The cruiser will take

\left(35\dfrac{\rm m}{\rm s}\right)-\left(5.0\dfrac{\rm m}{\mathrm s^2}\right)t=0\implies t=7.0\,\mathrm s

to come to a stop as it decelerates. It will have covered a total distance of

(137.5\,\mathrm m)+\left(35\dfrac{\rm m}{\rm s}\right)(7.0\,\mathrm s)+\dfrac12\left(-5.0\dfrac{\rm m}{\mathrm s^2}\right)(7.0\,\mathrm s)^2=\boxed{260\,\mathrm m}

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