Question

∠ADB and ∠BDC represent a linear pair because points A, D, and C lie on a straight line. Calculate the sum of m∠ADB and m∠BDC. Then move point B around and see how the angles change. What happens to the sum of m∠ADB and m∠BDC as you move point B around?

Answer 1

If points A, D and C lie on a straight line, then angles ∠ADB and ∠BDC are supplementary angles and
$m\angle ADB+m\angle BDC=180^{\circ}$.
1. If you move point B right from the initial position, then m∠ADB increases and m∠BDC decreases, but $m\angle ADB+m\angle BDC=180^{\circ}$.
2. If you move point B left from the initial position, then m∠ADB decreases and m∠BDC increases, but $m\angle ADB+m\angle BDC=180^{\circ}$.
3. When point B lie on the line ADC, then:
a. Point B lies on the right hand from point D: $m\angle ADB=180^{\circ} \\m\angle BDC=0^{\circ}$;
b. Point B lies on the left hand from point D: $m\angle ADB=0^{\circ} \\m\angle BDC=180^{\circ}$.
4. When point B is reflected about the line ADC situation is the same as in parts 1 and 2.

Conclusion: $m\angle ADB+m\angle BDC=180^{\circ}$.

Answer 2

Answer:

The sum of m∠ADB and m∠BDC remains the same: m∠ADB + m∠BDC = 180°.

Step-by-step explanation: