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Mariana [72]
3 years ago
14

A company sells two versions of an antivirus software. The home edition costs $23.50, and the business edition costs $58.75. Las

t week, the company earned $29,668.75 from selling 745 copies of the software.
If x represents the number of copies of the home edition sold and y represents the number of copies of the business edition sold, which system of equations represents this situation?
Mathematics
1 answer:
Kamila [148]3 years ago
6 0

Answer:

x + y = 745

23.50x + 58.75y = 29,668.75

Step-by-step explanation:

Since 745 copies were sold and  x represents the number of copies of the home edition sold and y represents the number of copies of the business edition sold:

x + y = 745

Since the home edition costs $23.50, and the business edition costs $58.75:

The money earned from home edition is = 23.50x

The money earned from business edition is = 58.75y

Since the company earned $29,668.75:

23.50x + 58.75y = 29,668.75

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A new factory in a small town has an annual payroll of ​$ million. It is expected that of this money will be spent in the town b
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Step-by-step explanation:

8 0
3 years ago
Please help I will give brainliest
pentagon [3]

The option that represents the answers for 6, 8, 10, and 14 is the second option-   31, 41, 51, 71

<h3>Sequence and Series </h3>

From the question, we are to determine the option that represents the answer for pictures 6, 8, 10, and 14

In the given diagram,

The first picture requires 6 matches

The 2nd picture requires additional 5 matches

the 3rd  picture requires additional 5 matches

and so on

That is

1 → 6

2 → 6 + 5 = 11

3 → 11 + 5 = 16

4 → 16 + 5 = 21

5 → 21 + 5 = 26

6 → 26 + 5 = 31

7 → 31 + 5 = 36

8 → 36 + 5 = 41

9 → 41 + 5 = 46

10 → 46 + 5 = 51

11 → 51 + 5 = 56

12 → 56 + 5 = 61

13 → 61 + 5 = 66

14 → 66 + 5 = 71

Hence, the option that represents the answers for 6, 8, 10, and 14 is the second option-   31, 41, 51, 71

Learn more on Sequence and Series here: brainly.com/question/10321751

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7 0
1 year ago
What are the approximate values of the non-integral roots of the polynomial equation?
irga5000 [103]

Answer:

-4, -2, -3-2i, -3+2i

Step-by-step explanation:

The of the polynomial equation are those values of x, for which f(x)=0.

Consider equation

f(x)=0\\ \\(x^2+6x+8)(x^2+6x+13)=0

By zero product property,

x^2+6x+8=0\ \text{or}\ x^2+6x+13=0

Solve each equation:

1. x^2+6x+8=0

D=6^2-4\cdot 8=36-32=4\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{4}}{2}=\dfrac{-6\pm 2}{2}=-4,\ -2

2. x^2+6x+13=0

D=6^2-4\cdot 13=36-52=-16=16i^2\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{16i^2}}{2}=\dfrac{-6\pm 4i}{2}=-3-2i,\ -3+2i

5 0
3 years ago
Read 2 more answers
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