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3 years ago

Y=? X=? HELP ASAP PLEASE

Mathematics

1 answer:

tia_tia [17]3 years ago

6 0

Answer:

y=1/2x-3

Step-by-step explanation:

I hope you meant slope of the line...

You can find the slope like this-

1/2x= how you move (so m for move)

-3 =where you begin (so b for begin)

So next time you find the slope, just ask yourself where you "begin" (where the line starts) and how you "move" (how the line moves)

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Which number is greater and by how much: A decreased by 50% and then increased by 50% of the result

cricket20 [7]

Answer:

the original number is greater

Step-by-step explanation:

1. let 1x be your starting number

2. therefore, 0.5 * 1x = 0.5x ( amount after you decreased it by 50%)

3. then increase: 0.5x * 1.5 = 0.75x (amount after you increased it by 50%)

4. 0.75x < 1x (this means that the original number is larger than the one you decreased and then increased)

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2 years ago

Water lilies are often used to decorate ponds, as shown in the photo. But they are also famous for their unusual growth pattern!

Alex17521 [72]

There really isn't a right or wrong answer since this is a prediction but to solve this look at the graph and try to see the pattern

5 0

3 years ago

Read 2 more answers

Check off the methods of differentiation required, and complete the derivative.

kogti [31]

Given:

$f(x)=\sqrt[]{5x^2-2}$

f(X) will be differentiated by chain rule.

$\begin{gathered} f^{\prime}(x)=\frac{1}{2\sqrt[]{5x^2-2}}\lbrack5(2x)\rbrack \\ f^{\prime}(x)=\frac{5x}{\sqrt[]{5x^2-2}} \end{gathered}$

6 0

1 year ago

4vir4ik [10]

Answer:

Tell in english plss

Step-by-step explanation:

i dont understangd okk

6 0

2 years ago

How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?

Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = $\dfrac{90000}{3}=30000$

n( divisible by 5) = $\dfrac{90000}{5}=18000$

n( divisible by 7) = $\dfrac{90000}{7}=12857.14$

n( divisible by 3 and 5) = n(3∩5)= $\dfrac{90000}{15}=6000$

n( divisible by 5 and 7) = n(5∩7) = $\dfrac{90000}{35}=2571.42$

n( divisible by 3 and 7) = n(3∩7) = $\dfrac{90000}{21}=4285.71$

n( divisible by 3,5 and 7) = n(3∩5∩7) = $\dfrac{90000}{105}=857.14$

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

$=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15$

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0

3 years ago