En Español
En la class de ciencias hay muchos estudiantes. A Irene siempre le gusta estudiar y haver la tarea. En todos los exámenes saca cien. Pablo nunca estudia y no le gusta tomar aptunes. En los exámenes saca cuarenta, cincuenta y trienta. Muchas veces, a Sandra le gusta hacer la tarea. En los exámenes saca noventa, cuarenta y cien. A Eduardo a veces le gusta estudiar y hacer la tarea. En los exámenes saca noventa, noventa y noventa. A Javier nunca le gusta leer libros. En los exámenes saca cuarenta, cincuenta y cuarenta. Todos los estudiantes son differentes y me gusta enseñar ciencias a todos.
In english
In science class there are many students. Irene always likes to study and do her homework. In all the exams he gets a hundred. Pablo never studies and does not like to take aptunes. In the exams he gets forty, fifty and thirty. Many times Sandra likes to do her homework. In the exams he gets ninety, forty and one hundred. Eduardo sometimes likes to study and do homework. In the exams he gets ninety, ninety and ninety. Javier never likes to read books. On the exams he gets forty, fifty and forty. All students are different and I like to teach science to everyone.
Hope this helps!
Answer:
Total number of texts sent by each person is as follows;
Jose=14
Bon=56
Ann=48
Step-by-step explanation:
Step 1
Express the total amount of texts sent by each person as shown;
Let the number of texts sent be;
Jose=x
Bon=4 times as Jose=4×x=4 x
Ann=sent 8 fewer than jose=4 x-8
Total texts sent=118
Step 2
Express the total number of texts sent by all of them as show;
Total texts sent=amount sent by Jose+amount sent by Bon+amount sent by Ann
where;
Total texts sent=118
amount sent by Jose=x
amount sent by Bon=4 x
amount sent by Ann=4 x-8
replacing;
118=x+4 x+4x-8
118=9 x-8
118+8=9 x
9 x=126
x=126/9
x=14
Step 3
Substitute the value of x to get the number of texts sent by each individual;
amount sent by Jose=x=14
amount sent by Bon=4 x=(4×14)=56
amount sent by Ann=4 x-8=56-8=48
Total number of texts sent by each person is as follows;
Jose=14
Bon=56
Ann=48
In the balanced reaction
2 Fe + O₂ → 2 FeO
2 moles of iron (Fe) react with 1 mole of molecular oxygen (O₂) to produce 2 moles of iron oxide (FeO). The ratio of Fe to FeO is 1-to-1, so if one starts with 42.4 mol of Fe, one will end up with the same amount of FeO, 42.4 mol.
Look up the molar mass of Fe and O:
• Fe = 55.845 g/mol
• O = 15.999 g/mol
Then the molar mass of FeO is approximately 71.835 g/mol, and so the mass of 42.4 mol of FeO is
(42.4 mol) × (71.835 g/mol) ≈ 3050 g