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gizmo_the_mogwai [7]
4 years ago
15

James defines a circle as "the set of all the points equidistant from a given point." His statement is not precise enough becaus

e he should specify that
Mathematics
2 answers:
Setler [38]4 years ago
8 0
Okay so James needs to define a circle
Zinaida [17]4 years ago
6 0

Answer: The answer is "the set of points is in a plane "

Step-by-step explanation: In the given question, James' statement does not precise because he defines a circle as its collection of the equal distance from one point to just another given point., and his preamble wasn't accurate because it is meant designed and determine the all set of points mostly on the plane, that's why the choice "set of points in its plane" is the correct.

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A long distance runner ran 4x4x4x4x4x4 miles last year. How many miles is this?
Archy [21]

Answer:

4096

Step-by-step explanation:

4x4x4x4x4x4=4^6

Group them to multiply to make it easier:

4x4=16

4x4=16

4x4=16

16x16x16=4096

honestly just plug it into a calculator

3 0
3 years ago
Read 2 more answers
Please help me with this!
blsea [12.9K]

Answer:

180

Step-by-step explanation:

So, lets go over what we know:

5% of x = 9

Thinking of this in decimal form, this is:

0.05 * x = 9, or 0.05x = 9

To find the answer, we must multiply both sides to get 1x.

Since 0.05 is 1/20 of 1, we must multiply both sides by 20:

0.05x * 20 = 0 * 20:

1x = 180

So the answer is 180!

Hope this helps!

7 0
3 years ago
Please help this is unit rates btw :)
Volgvan

Answer: 17.14 pages per day

Step-by-step explanation:

3 0
3 years ago
Iq scores are measured with a test designed so that the mean is 116116 and the standard deviation is 1818. consider the group of
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5 0
4 years ago
Find the exact values of sin A and cos A. Write fractions in lowest terms. (5 points) A right triangle ABC is shown. Leg AC has
swat32

sin\ A = \frac{4}{5}\\\\cos\ A = \frac{3}{5}

<em><u>Solution:</u></em>

Given a right triangle ABC

The figure is attached below

From given,

AC = Base = 33

BC = Perpendicular = 44

AB = hyptotenuse = 55

We know that,

Sin\ A = \frac{perpendicular}{hypotenuse}\\\\Sin\ A = \frac{44}{55}\\\\Sin\ A = \frac{4}{5}

Also,

cos\ A = \frac{base}{hypotenuse}\\\\cos\ A = \frac{33}{55}\\\\cos\ A = \frac{3}{5}

Thus the values are found

6 0
3 years ago
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