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3 years ago

water weighs about 8.34 pounds per gallon. About how many ounces per gallon is the weight of the water?

1 answer:

3 0

Use a conversion factor and turn pounds to ounces. 1 pound = 16 ounces so
$\frac{8.34pounds}{gallon} \times \frac{16 ounces}{ 1 pound} =133.44 \frac{ounces}{gallon}$

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Which point best approximates ? A B C D

snow_lady [41]

√36 = 6

√49 = 7

√45 is between 6 and 7

so √45 must be less than 7 but close to 7

Estimate answer is C.

6 0

3 years ago

Read 2 more answers

A water truck is filling a swimming pool. The equation that represents this

Luda [366]

Answer:

a. false

b. true

c. true

d. true

e. false

Step-by-step explanation:

a. False. The "unit rate" is 19.75 gallons per minute. The "unit" of a "unit rate" is in the denominator. Here, the denominator of the rate is 1 minute.

b. True. A graph of a proportional relationship is a straight line through the origin.

c. True. In 5 minutes, the water in the pool will increase by 98.75 gallons, about 100 gallons.

d. True. The ratio of a y-value to an x-value will always be 19.75. That is the meaning of this proportional relationship.

e. False. The points (8, 158) or (7.5949, 150) will be on the graph. The point (8, 150) will not.

8 0

3 years ago

NEED HELP WITH THESE QUESTIONS

amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

$\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =$

Applying double C we have:

$\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =$

By definition of multiplication of powers of the same base we have to place the same base and add the exponents: $\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =$

Canceling common terms:

$\frac {mn ^ 5} {p ^ 4}$

Answer:

Option A

Question 2:

We should simplify the following expression:

$\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}$

So, we have:

$\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =$

Simplifying common terms:

$\frac {1} {y ^ 2z ^ 2}$

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

$r ^ 2 + 7r + 10$ : We look for two numbers that multiplied give 10 and added 7:

$(r + 5) (r + 2)$

$r ^ 2-5r-50:$ We look for two numbers that multiplied give -50 and added -5:

$(r-10) (r + 5)$

$3r-30 = 3 (r-10)$

Rewriting the given expression we have:

$\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =$

We simplify common terms in the numerator and denominator we have:

$(r + 2)$

Answer:

Option D

4 0

3 years ago

Read 2 more answers

Determine if the sequence is arithmetic. If it is, find the common difference. Is the sequence a function ?

BaLLatris [955]

$6)\\r=a_{n+1}-a_n\to r=a_2-a_1=a_3-a_2=a_4-a_3=...\\\\a_1=-7;\ a_2=-10;\ a_3=-11;\ a_4=-13\\\\a_2-a_1=-10-(-7)=-10+7=-3\\a_3-a_2=-11-(-10)=-11+10=-1\\\\a_3-a_2\neq a_2-a_1\\\\\text{It's not an arithmetic sequence}$

$\r=\dfrac{a_{n+1}}{a_n}\\\\r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...\\\\8.)\\a_1=4;\ a_2=20;\ a_3=100;\ a_4=500\\\\r=\dfrac{20}{4}=\dfrac{100}{20}=\dfrac{500}{100}=5\\\\10.)\\a_1-30;\ a_2=-45;\ a_3=-50;\ a_4=-65\\\\\dfrac{a_2}{a_1}=\dfrac{-45}{-30}=\dfrac{3}{2}\\\\\dfrac{a_3}{a_2}=\dfrac{-50}{-45}=\dfrac{10}{9}\\\\\dfrac{a_2}{a_1}\neq\dfrac{a_3}{a_2}\\\\\text{It's not a geometric sequence}$
$12.)\\a_1=-7;\ a_2=-14;\ a_3=-21;\ a_4=-28\\\\\dfrac{a_2}{a_1}=\dfrac{-14}{-7}=2\\\\\dfrac{a_3}{a_2}=\dfrac{-21}{-14}=\dfrac{3}{2}\\\\\dfrac{a_2}{a_1}\neq\dfrac{a_3}{a_2}\\\\\text{It's not a geometric sequence}\\\\\text{It's a function}$

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3 years ago

Helen plays basketball. For free throws, she makes the shot 78% of the time. Helen must now attempt two free throws. C = the eve

riadik2000 [5.3K]

Answer:

0.6708 or 67.08%

Step-by-step explanation:

Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:

$P(C+D) = P(C) *P(D|C) = 0.78*0.86\\P(C+D) = 0.6708$

There is a 0.6708 probability that Helen makes both free throws.

5 0

3 years ago