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-Dominant- [34]
3 years ago
15

water weighs about 8.34 pounds per gallon. About how many ounces per gallon is the weight of the water?

Mathematics
1 answer:
notka56 [123]3 years ago
3 0
Use a conversion factor and turn pounds to ounces. 1 pound = 16 ounces so
\frac{8.34pounds}{gallon} \times \frac{16 ounces}{ 1 pound} =133.44 \frac{ounces}{gallon}
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Step-by-step explanation: I took the test

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4 0
4 years ago
What’s the answer ? Lol
kvasek [131]
Answer: 35.36

----------------------------

Work Shown:

N(t) = N0*(1/2)^(t/5730)
N(t) = 200*(1/2)^(t/5730)
N(14325) = 200*(1/2)^(14325/5730)
N(14325) = 200*(1/2)^(2.5)
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You were fairly close to the answer

7 0
3 years ago
Answer?? please answer
Maru [420]

Answer:

The y-value of Function A when x = 2 is GREATER than the y-value of Function B when x = 2

Step-by-step explanation:

✔️Find the equation of Function A:

To do this, find the y-intercept (b) and slope (m):

Slope (m) = change in y/change in x

Using (4, 13) and (5, 17),

Slope (m) = (17 - 13)/(5 - 4) = 4/1

m = 4

To find b, substitute (x, y) = (4, 13) and m = 4 into y = mx + b

13 = 4(4) + b

13 = 16 + b

13 - 16 = b

b = -3

To write the equation for Function A, substitute m = 4 and b = -3 into y = mx + b

Thus:

y = 4x - 3

Next, find the y-value of Function A when x = 2 by substituting x = 2 into y = 4x - 3

Thus:

y = 4(2) - 3

y = 8 - 3

y = 5

✅The y-value of Function A when x = 2 is 5

✔️Equation for Function B is given as,

y = ½x + 1

Find the y-value of Function B when x = 2 by substituting x = 2 into y = ½x + 1

Thus:

y = ½(2) + 1

y = 1 + 1

y = 2

✅The y-value of Function B when x = 2 is 2

Therefore, the correct statement is:

The y-value of Function A when x = 2 is greater than the y-value of Function B when x = 2

8 0
3 years ago
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