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Oliga [24]
3 years ago
10

What is the area?Please i need help

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

Answer:

65

Step-by-step explanation:

Base by High

then divided by 2

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Solve and show all work and make sure its correct, and makes sense.(Multiple transformations)
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Add 5 to both sides
n/3-5=12
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4 years ago
Ferroza can buy a 24-ounce bag of ferret food for $1.19, or she can buy a 36-ounce bag for $2.89. Which is the better deal? Just
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Answer:the 24 for 1.19 is the better deal

Step-by-step explanation:

1. 1.19 ÷24 =4.95

2.2.89÷36=8.5

3. It cost less for 1 can than the 8.5 dollar can.

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3 years ago
When rabbits were introduced to the continent of Australia they quickly multiplied and spread across the continent since there w
Lady bird [3.3K]

Answer:

a. y=6(1.7472)^x

b. y=6e^{0.558t}

c.13.3 months

Step-by-step explanation:

a.-Given the first term  at t_0 is 6 and the second term at t_3 is 32.

-Let's take rabbit population as a function of time to be

y=ab^x

where y is the population at time x and a the initial population at t_0\\

#We substitute our values to calculate the value of the constant b:

y_x=ab^x\\\\y_3=ab^3\\\\32=6b^3\\\\b=1.472

#Replace b in the population function:

y=ab^x, b=1.7472,a=6\\\\\therefore y=6(1.7472)^x

Hence, the regression for the rabbit population as a function of time x is y=6(1.7472)^x

b. The exponential function in terms of base e is usually expressed as:

A=A_0e^{kt}

Where:

A_0-is the initial population at t_o

A-is the population at time t.

k-is the  exponential growth constant.

e- the exponent

Our function in terms of base exponent is rewritten as:

y=A_0e^{kt}

#Substitute with actual figures to solve for t:

y=A_0e^{kt}, y=32, xt=3, A_0=6\\\\32=6e^{3k}\\\\3k=In (32/6)\\\\k=0.5580

Hence, the regression equation in terms of base e is y=6e^{0.558t}

c. We substitute y with any number higher than 10,000 to estimate the time for the rabbits to exceed 10,000.

-We know that y=6e^{0.558t}.

Therefore we calculate t as(take y=10001):

y=6e^{0.558t}, y=10001\\\\10001=6e^{0.558t}\\\\1666.8333=e^{0.558t}\\\\0.558t= In 1666.8333\\\\t=13.2951

Hence, it takes approximately 13.3 months for the population to exceed 10000

3 0
4 years ago
I dont know how to solve this one ​
Olenka [21]

Answer:

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