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OLEGan [10]
3 years ago
6

A an elevator in a mine is going up and down. The inequality statements compare the elevation of the elevator at three different

points.
–250 m < –131 m

–131 m < –102 m



Which statements comparing the elevations are true?



Select each correct statement.



An elevation of –131 m is lower than an elevation of –250 m .

An elevation of –102 m is higher than an elevation of –131 m .

An elevation of –250 m is lower than an elevation of –102 m .

An elevation of –131 m is higher than an elevation of –102 m
Mathematics
1 answer:
ioda3 years ago
4 0
Both statements 2 and 4 are correct

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LaTanya says that the growth factor of f(x) = 100(1.25) is 25%. What mistake did LaTanya make?
vladimir2022 [97]

Answer:

The first error consists in the multiplication of f (x) = 100 * (1.25), the value she mentions is incorrect since it is 125.

It would be a 125% increase really.

In order for LaTanya's phrase to have no error she had to mention that it was a 25% increase over the original amount, in this way, the phrase would make sense and be valid.

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A proton initially has and then 8.00 s later has (in meters per second). (a) For that 8.00 s, what is the proton's average accel
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Answer:

Some details are missing in the question, here are the details ; A proton initially has v = -6.5i + 17j + 13k and then 8.00s later has v = -2.8i + 17j - 9.3k (in meters per seconds).

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Step-by-step explanation:

The detailed and step by step explanation is as shown in the attachment

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6 0
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Read 2 more answers
A new computer loses 1/2 of its value every year. Which graph could represent the relationship between the year and the computer
Igoryamba

<u>Let's first consider:</u><em> the fact that a new computer loses 1/2 of its value</em>

<em> </em>  ⇒ <u>third choice</u> and <u>fourth choice</u> are <u>eliminated</u>

    ⇒ because of the graph project the computer's value as growing over  

         years

<u>Now let's try to set up an equation</u>:

After 1st year ⇒ Computer's value = total_.value*\frac{1}{2}

After 2nd year ⇒ Computer's value = total_.value*\frac{1}{2}*\frac{1}{2}=total_.value*(\frac{1}{2}  )^2

After 3rd year ⇒ Computer's value =total_.value*\frac{1}{2}*\frac{1}{2}* \frac{1}{2}=total_.value*(\frac{1}{2})^3

     

 ..... (<em>Hopefully you see a pattern)</em>

<em />

After x year ⇒ Computer's value = total_.value*(\frac{1}{2})^x

<u>Therefore, the equation is</u>: total_.value*(\frac{1}{2})^x

  ⇒that means the graph has to <u>exponentially decreasing</u> as it has

     an exponent (<em>meaning the function is exponential</em>) and a base less

     than 1 (<em>meaning that the function is decreasing)</em>

<u>Answer: Choice (1)</u>

<u></u>

Hope that helps!

5 0
2 years ago
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