Answer:
Assuming you have
with
, the answer is f(2)=13.6.
Step-by-step explanation:
I think that says
with
.
Now we want to find
so replace n with 2:
This gives you:





The first step I would take is
.. Multiply both sides of the equation by 1/4.
_____
You could start by adding 16 to both sides of the equation, to make the left side the square (2x +4)^2.
Answer:
The approximated length of EF is 2.2 units ⇒ A
Step-by-step explanation:
<em>The tangent ratio in the right triangle is the ratio between the opposite side to the adjacent side of one of the acute angle in the triangle</em>
In the given figure
∵ The triangle DFE has a right angle F
∵ The opposite side to angle D is EF
∵ The adjacent side to angle D is DF
→ By using the tangent ratio above
∴ tan(∠D) = 
∵ DF = 6 units
∵ m∠D = 20°
→ Substitute then in the ratio above
∴ tan(20°) = 
→ Multiply both sides by 6
∴ 6 tan(20°) = EF
∴ 2.183821406 = EF
→ Approximate it to the nearest tenth
∴ 2.2 = EF
∴ The approximated length of EF is 2.2 units
I have a link but it’s not fake
Answer: rs 4800, rs 3456
Step-by-step explanation:j
given data:
length of a sid = 48m
cost of ploughing the field = rs 25/m
cost of fencing the field = rs 18/m
solution:
we know a square has four equal sides. so total length of the field is
= m ( 48 + 48 +48 + 48 )
= 192m
cost of ploughing the field
= 192m * rs 25
= rs 4800
cos of fencing the field
= 192m * rs 18
= rs 3456