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3 years ago

10 PTS AND MARK BRAINLEST!!!! PLZZZZ HELLLPPP!!!!

Mathematics

1 answer:

serg [7]3 years ago

4 0

Ok so the first one is 225 miles but i can't do the graph
and i'm not great at math so give me a bit

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Ms. Putnam is taking a group of students to a basketball game. Tickets to the basketball game cost $8 each. For each ticket that

Volgvan

Answer:

8x + 1x + 2x = $$

Step-by-step explanation:

I think this is the answer

5 0

3 years ago

Saul makes green paint by mixing blue paint and yellow paint.

oksano4ka [1.4K]

You should include a picture so I could tell you the answer

5 0

3 years ago

Read 2 more answers

David and Amanda are trying to figure out how long they can live off their $12,350 savings if they spend $240 each month. They h

Alecsey [184]

Hey there! :)

Answer:

Choice 3: David's equation is correct because their spending will be multiplied by the number of months and then subtracted from their savings.

Step-by-step explanation:

In the question, $12,350 is given as the initial value and '240x' is the monthly spending in terms of x.. When writing the equation, we must subtract 240x because the money is being spent.

The correct equation for this situation would be:

y = 12,350 - (240x).

Thus, David's Equation is correct.

7 0

3 years ago

A new, simple test has been developed to detect a particular type of cancer. The test must be evaluated before it is used. A med

g100num [7]

Answer:

0.3333 = 33.33% probability of a randomly chosen person not having cancer given that the test indicates cancer

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test indicates cancer.

Event B: Person does not have cancer.

Probability of a test indicating cancer.

98% of 2%(those who have).

1% of 100 - 2 = 98%(those who do not have). So

$P(A) = 0.98*0.02 + 0.01*0.98 = 0.0294$

Probability of a test indicating cancer and person not having.

1% of 98%. So

$P(A \cap B) = 0.01*0.98 = 0.0098$

What is the probability of a randomly chosen person not having cancer given that the test indicates cancer?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0098}{0.0294} = 0.3333$

0.3333 = 33.33% probability of a randomly chosen person not having cancer given that the test indicates cancer

3 0

3 years ago

Work out the percentage change when a price of £25 is increased to £30

vazorg [7]

Answer: i believe its 20% Im not entirley sure.

Step-by-step explanation:(V2−V1)|V1|×100

=(30−25)|25|×100

=525×100

=0.2×100

=20%change

=20%increase

\_(~.~)_/ idek

7 0

3 years ago