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KonstantinChe [14]

3 years ago

9

Please help find the rate?

1 answer:

Ratling [72]3 years ago

7 0

9.09 is what your looking for.

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A grocery store has small bags of apples for $5 and large bags of apples for $8. If you buy 6 bags and spend $45, how many of ea

ladessa [460]

Based on the given problem above, here is the given solution.
Given that small bags = $5
large bags = $8
6 bags = $45
? = number of each size bag you bought
The answer based on the given values above is 5 LARGE BAGS and 1 SMALL BAG.
Since per large bag is $8. $8 x 5 = $40
And per small bag is $5 x 1 = $5
So this gives you a total of $45
hope this helps!

3 0

4 years ago

oksian1 [2.3K]

Answer:

9 units

Step-by-step explanation:

By the midsegment theorem,

$AB=\dfrac{KN+LM}{2}$

Since the ratio $LM:KN=1:5,$ then $LM=x,\ KN=5x$ and

$18=\dfrac{x+5x}{2}\\ \\18=\dfrac{6x}{2}\\ \\18=3x\\ \\x=6\\ \\LM=6\ units\\ \\KN=30\ units$

Draw two heights LE and MF. Quadrilateral ELMF is a rectangle, then EF = LM = 6 units.

Trapezoid KLMN is isosceles trapezoid (KL = MN), then KE = FN and

$KE=FN=\dfrac{KN-EF}{2}=\dfrac{30-6}{2}=12\ units$

Consider right triangle KLE. By the Pythagorean theorem,

$KL^2=LE^2+KE^2\\ \\15^2=LE^2+12^2\\ \\LE^2=15^2-12^2\\ \\LE^2=225-144=81\\ \\LE=9\ units$

3 0

3 years ago

Convert the following equation into<br> slope-intercept form.<br> x + y = -1

madam [21]

Answer:

y=-x-1

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A clothing salesman want to earn $6000 in March. He receives a base salary of $4000 per mont as well as a 10% commission for all

N76 [4]

He would have to sell $20,000 worth of clothes to get $2,000

6 0

3 years ago

swat32

Answer:

$\log_{10}(147) = 2.1673$

Step-by-step explanation:

Given

$\log_{10} 3 = 0.4771$

$\log_{10} 5 = 0.6990$

$\log_{10} 7= 0.8451$

$\log_{10} 11 = 1.0414$

Required

Evaluate $\log_{10}(147)$

Expand

$\log_{10}(147) = \log_{10}(49 * 3)$

Further expand

$\log_{10}(147) = \log_{10}(7 * 7 * 3)$

Apply product rule of logarithm

$\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)$

Substitute values for log(7) and log(3)

$\log_{10}(147) = 0.8451 + 0.8451 + 0.4771$

$\log_{10}(147) = 2.1673$

3 0

3 years ago