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HACTEHA [7]
3 years ago
15

Construct a confidence interval for μd, the mean of the differences d for the population of paired data. Assume that the populat

ion of paired differences is normally distributed. A test of writing ability is given to a random sample of students before and after they completed a formal writing course. The results are given below. Construct a​ 99% confidence interval for the mean difference between the before and after scores.
Before 70 80 92 99 93 97 76 63 68 71 74
After 69 79 90 96 91 95 75 64 62 64 76
Mathematics
1 answer:
Lynna [10]3 years ago
6 0

Answer:

Step-by-step explanation:

Group Before After

Mean 80.27 78.27

SD 12.76 12.92

SEM 3.85 3.89

N 11 11

df = 10

standard error of difference = 0.798

The mean of Before minus After equals 2.00

Given a=0.01, |t(0.005, df=10)|=3.17 (check student t table)

So 99% CI is

2±t*s

--> 2±3.17*0.798

--> -0.5 < µd< 4.5

Answer:-0.5 < µd< 4.5

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Mike observed that 75% of the students of a school liked skating. If 35 students of the school did not like skating, the number
kati45 [8]

Answer:

75

Step-by-step explanation:

If 75% of the students like skating, that means 35% of the students don't like skating.

35% of the students corresponds to 35 students that do not like skating.

Then to find the number of students who like skating we use the following logical computation,

35% represents 35 people then how much does 75% represent

⇒\frac{35}{35%} *75%

=75

Therefore,

The number of students who like skating was 75.

3 0
3 years ago
There are 20 percent more goblins than wizards in magic club. There are 120 goblins in magic club.
sineoko [7]

Answer:

144

Step-by-step explanation:

120 x 1.20 = 144

.20 is 20% and adding the 1 adds it to the original value

5 0
3 years ago
A pan of lasagna cut into 100 servings is equally shared among a group of people. For Exercises
Volgvan

53).  100 servings / 20 people  =  (100/20) (svngs/ppl)

                                                 = 5 servings per person.

         Each person gets 1/20 = 5% = 0.05 of the pan.


54).  100 servings / 40 people  =  (100/40) (svngs/ppl)

                                                 = 2.5 servings per person.

         Each person gets  1/40 = 2.5% = 0.025 of the pan.


55).  100 servings / 30 people  =  (100/30) (svngs/ppl) 

                                                  = (3 and 1/3) servings per person.

         Each person gets  1/30 = (3 and 1/3) % = 0.0333... of the pan.
 
3 0
3 years ago
Based on experience, the probability that an incoming email is spam (an undesired message of solicitation) is 38%. If three emai
SCORPION-xisa [38]

Answer:

0.0549

0.7617

0.2383

Step-by-step explanation:

Given that:

Probability that incoming email is spam ;

P(spam) = 0.38

If three emails are in my inbox, what is the probability that:

A. All three messages are spam.

P(1st message being spam) * p(second message being spam) * p(3rd message being spam)

= (0.38) * (0.38) * (0.38)

= 0.054872

= 0.0549

B. At least one of the three messages are spam.

1 - p(none of the 3 messages are spam)

P(none of the 3 messages are spam)

P(not spam) = 1 - p(spam) = 1 - 0.38 = 0.62

1 - [P(not spam) * p(not spam) * p(not spam)]

1 - (0.62 * 0.62 * 0.62)

= 1 - 0.238328

= 0.761672

= 0.7617

C. None of the three messages are spam.

P(not spam) = 1 - p(spam) = 1 - 0.38 = 0.62

P(not spam) * p(not spam) * p(not spam)

(0.62 * 0.62 * 0.62)

= 0.238328

= 0.2383

7 0
3 years ago
Yoshi is riding a bike-a-thon to raise money for his favorite charity The total distance of the bike-a-thon is 28.5 miles So far
polet [3.4K]
He has biked 2.85 miles. By multiplying 28.5 and 0.10 or dividing 28.5 by 10 you get the total 2.85. To check your answer you can multiply 2.85 by 10 which equals 28.5. Hope this helps!
6 0
4 years ago
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