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laila [671]
3 years ago
7

Easy point to earn

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0
Yeah that's correct
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EMERGENCY QUESTION! No Decimal answers plz!
telo118 [61]

Answer:

1,145,375 cm³

Step-by-step explanation:

Like with an earlier question you had, there is a chunk missing. If that chunk was filled in, this would be a 205 * 70 * 85 rectangular prism.

205 * 70 * 85

17,425 * 70

1,219,750

The cut out chunk is a 25 * 70 * 85 triangular prism.

1/2 (25 * 70 * 85)

1/2(2,125 * 70)

1/2(148,750)

74,375

Now that we know what the cut-out chunk is, subtract that from the first value we got.

1,219,750 -74,375

1,145,375 cm³

The volume of the Canadian Post mailbox is 1,145,375 cm³.

8 0
2 years ago
Read 2 more answers
What is the value of 5^3i^9
Tema [17]

Answer:

5^(3)i^(9)= five cubes times i to the power of 9=125i

Step-by-step explanation:

Raise 5 to the power of 3

rewrite i9 as (i^4)2^i

so, you get 125((i^4)^2i)

i^4=1

125(1^2i)

125i

4 0
2 years ago
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

V_{flask}=V_{sphere}+V_{cylinder}.

Use following formulas to determine volumes of sphere and cylinder:

V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

  • V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;
  • V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;
  • V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.

Then

\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.

Answer 2: correct choice is D.


8 0
3 years ago
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The formula for the area of a trapezoid is A = h(b1 + b2), where A = area, h = height, b1 = base 1, and b2 = base 2. For a trape
enyata [817]
The area of the trapezoid is A= 56
5 0
3 years ago
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How did you determine ray​
Effectus [21]

Answer:

In naming a ray, we always begin with the letter of the endpoint (where the ray starts) followed by another point on the ray in the direction it travels. Since the vertex of the angle is the endpoint of each ray and our vertex is , each of our rays must begin with . Only fails to do so.

3 0
2 years ago
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