Baseball game math problem

In a class of 55 students, 15 students like Math but not English and 18 students liked English but not Math. If 5 students did n

Viefleur [7K]

See the venn-diagram in the picture.

Hope this helps! Please consider marking me the Brainliest, it’s not necessary, but very much appreciated. Have a great day!

6 0

3 years ago

Is the number rational or irrational? Explain. A. -38 B. 400 C. 2 3 27

Alik [6]

A. No, because -38 isn't a fraction.

2, No because 400 is a real number.

3. Yes because fractions, decimals, and percents are rational numbers.

hope that helped

6 0

3 years ago

A stack of playing cards contains 4 jacks, 5 queens, 3 kings, and 3 aces. two cards will be randomly selected from the stack. wh

Kipish [7]

Answer:

1/9.

Step-by-step explanation:

There is a total of 15 cards in the stack.

Prob( Queen is chosen) = 5/15 = 1/3.

The probability of a second queen being chosen is also 1/3

Required probability = 1/3 * 1/3 = 1/9.

7 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

4 years ago

99 point please help

____ [38]

It wants it to be in slope-intercept form.

y=mx+b

We have to first find the slope and plug it into point-slope form.

y-y1=m(x-x1)

Find the slope of the second line. (I did this one first on accident)

Rise/run= 3/1= 3 The slope is 3. Plug that in along with the point (0,3)

y-3=3(x-0)
y-3=3x

Add 3 to the other side.

y= 3x +3 <- for the second line

Now, the second.

rise/run= 1/2= .5 Use point (6,0)

y-0=.5(x-6)
y= .5x-3

y=.5x-3 <- for the first line

I hope this helps!
~kaiker

4 0

3 years ago

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