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Usimov [2.4K]
3 years ago
15

What id the height of the triangle?​

Mathematics
2 answers:
Triss [41]3 years ago
5 0

Answer:

6.5 cm

Step-by-step explanation:

Serhud [2]3 years ago
4 0
The answer to this question is 6.5
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Evaluate in the following expression when x = 4 and y = 5​
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Fraction with x squared plus y cubed in the numerator and 2 plus x in the denominator.
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14.83
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7 0
2 years ago
(08.01 MC)
Colt1911 [192]

Part A:

We see that this pair of equations has 1 solution. On a graph, the solutions of 2 (or more) lines is where the lines intersect. In this case, since these lines intersect 1 time, they have 1 solution.

Part B:

As previously mentioned, the solutions of multiple lines is where the lines intersect. In this case, since they intersect at (4,4), that is the solution.

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shepuryov [24]

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Step-by-step explanation:

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2 years ago
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
2 years ago
Which numbers are composite numbers? Select all that are true
GuDViN [60]

Answer:

49

35

32

Hope this helped!

3 0
3 years ago
Read 2 more answers
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