Answer:
I may be wrong but I think 8 is your answer.
Step-by-step explanation:
(-1)^(3/7) x 128^(3/7)
-1 x 128^3/7
128^(3/7) = 8
= 8
The answer is D) Yes; because x and y must be integers, and integers are rational.
(6-8)/(1+2)= -2/3 the answer to the question
X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
