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shtirl [24]
3 years ago
12

I’m doing operations and interfers Need the answer have a test tmr

Mathematics
1 answer:
arsen [322]3 years ago
5 0

Answer:

all work for both worksheets are pictured and shown

Step-by-step explanation:

worksheet 2

28. 968/22=44

29. 27+8=35

30. 39×37=-1443

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Use the least common denominator to enter an equivalent fraction for each fraction.
OLga [1]

Answer:

1,7 1/7+

Step-by-step explanation:

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3 years ago
If f(x) = 2x+4 and g(x) = x^2-3 find each value
Ann [662]

1. 2(-3) + 4

 -6 + 4 = -2

2. -4^2 - 3

   16 - 3 = 13

3.  2 (m + 2) + 4

   2m + 4 + 4

   2m + 8

   2m = -8

   m = -4

4. i forgot how to do this. sorry :'(

7 0
3 years ago
What is the area of the composite figure O120 O100 O110 O90
ElenaW [278]

Total area is 110 square meter

4 0
3 years ago
In the United States, 7% of all registered voters belong to the Green party. A random sample of 50 registered voters is taken. U
Maksim231197 [3]

Answer:

The expected value of the sample proportion is of 0.07.

1. P(p < .02) = 0.0823

2. P(p > .15) = 0.0132

3. P(.05 < p < .09) = 0.4176

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

7% of all registered voters belong to the Green party. 50 voters:

This means that p = 0.07, n = 50

So, for the normal distribution:

\mu = 0.07, s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.07*0.93}{50}} = 0.036

The expected value of the sample proportion is of 0.07.

1. Determine P(p < .02).

This is the pvalue of Z when X = 0.02. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.02 - 0.07}{0.036}

Z = -1.39

Z = -1.39 has a pvalue of 0.0823

So

P(p < .02) = 0.0823

2. Determine P(p > .15).

This is 1 subtracted by the pvalue of Z when X = 0.15. So

Z = \frac{X - \mu}{s}

Z = \frac{0.15 - 0.07}{0.036}

Z = 2.22

Z = 2.22 has a pvalue of 0.9868

1 - 0.9868 = 0.0132

So

P(p > .15) = 0.0132

3. Determine P(.05 < p < .09).

This is the pvalue of Z when X = 0.09 subtracted by the pvalue of Z when X = 0.05. So

X = 0.09

Z = \frac{X - \mu}{s}

Z = \frac{0.09 - 0.07}{0.036}

Z = 0.55

Z = 0.55 has a pvalue of 0.7088

X = 0.05

Z = \frac{X - \mu}{s}

Z = \frac{0.05 - 0.07}{0.036}

Z = -0.55

Z = -0.55 has a pvalue of 0.2912

0.7088 - 0.2912 = 0.4176. So

P(.05 < p < .09) = 0.4176

3 0
3 years ago
Bryce has $16 more than Corey. Both have a combined total of $50. How much money does Bryce have.
LekaFEV [45]

Answer:

$33

Step-by-step explanation:

Let the amount of money Corey has be $x.

Amount of money Bryce have= $(x +16)

Total amount= $50

$x +$(x +16)= $50

2x +16= 50

2x= 50 -16

2x= 34

Divide both sides by 2:

x= 34 ÷2

x= 17

Amount of money Bryce have

= $(17 +16)

= $33

4 0
3 years ago
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