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andreyandreev [35.5K]

3 years ago

15

Can you help me solve this question? Cara has a list of all 720 students in her middle school. she write the name of each studen

t on a slip of paper and put each slip in a box. then she pulls 30 names from the box to decide Who she will survey about the upcoming school election.
question

what are different attributes of students or different groups of students that should be represented in the sample?

2 answers:

igor_vitrenko [27]3 years ago

5 0

Answer:

randomly select 10. Listen to Persian music

Step-by-step explanation:

Just listen to Aron Afshar.

Delicious77 [7]3 years ago

3 0

They have to all be middle school students.

You might be interested in

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

How is this equation completed? I cannot find any examples in the book.

djverab [1.8K]

Answer: Option D

$t_{max} =19\ s$

Step-by-step explanation:

Note that the projectile height as a function of time is given by the quadratic equation

$h = -12t ^ 2 + 456t$

To find the maximum height of the projectile we must find the maximum value of the quadratic function.

By definition the maximum value of a quadratic equation of the form

$at ^ 2 + bt + c$ is located on the vertex of the parabola:

$t_{max}= -\frac{b}{2a}$

Where $a$

In this case the equation is: $h = -12t ^ 2 + 456t$

Then

$a=-12\\b=456\\c=0$

So:

$t_{max} = -\frac{456}{2*(-12)}$

$t_{max} =19\ s$

7 0

3 years ago

Iteru [2.4K]

answer:

x = 0.80

y = 1.50

step-by-step explanation:

x = cost of tacos

y = cost of burritos

both equations:

3x + 2y = 5.40

2x + 1y = 3.10

^

turn this | into this |

v

y = 3.10 - 2x

then add it to the equation :

3x + 2 [ 3.10 - 2x ] = 5.40

3x + 6.2 - 4x = 5.40

-1x = - 0.8

x= 0.80

then add x = 0.80 to the equations to get :

3 [ 0.80 ] + 2y = 5.40

2.4 + 2y = 5.40

2y = 3

y = 1.5

5 0

3 years ago

I rlly need help with this guys please help me

makvit [3.9K]

24.1 times24 times 3.5times 2. Is 271ft2

6 0

3 years ago

PLEASE HELP 99 POINTS

statuscvo [17]

Presumably, $h(x)=3(5)^x$ . In that case,

(A)
The average rate of change over the interval $0\le x\le1$ is

$\dfrac{h(1)-h(0)}{1-0}=\dfrac{15-3}1=12$

and over $2\le x\le3$ , it's

$\dfrac{h(3)-h(2)}{3-2}=\dfrac{375-75}1=300$

(B)
$\dfrac{300}{12}=25$ , i.e. the average rate of change over the second interval is 25 times higher. That's to be expected; $3(5)^x$ is an exponential function. As $x$ gets larger, the rate of change of $h(x)$ gets larger too.

7 0

3 years ago