Answer:
(For the first two questions I do believe that you will need a protractor to calculate the angles.)
15) 
measures out to -70° in order to display that the angle would be in quadrant IV (the bottom right quadrant.)
The first image attached shows where the angle should be located.
16) 
is equal to 60° (the line you draw will be in quadrant 1 (the top right quadrant))
17) 350° is 
or 6.11 (the answer depends on the format the professor wants.)
18) 240° is 
radians or -4.19 (I am rounding to the nearest hundredths place the unsimplified answer is −4.18879020...)
Answer:
<h2>
<em>7</em><em>2</em><em>.</em><em>9</em><em>°</em></h2>
<em>sol</em><em>ution</em><em>,</em>
<em>
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
Answer:
QR = 65.4 m
Step-by-step explanation:
a. Apply Law of Cosines to find QR:
p² = q² + r² - 2qr × Cos P
p = QR = ?
q = PR = 150 m
r = PQ = 120 m
P = 25°
Plug in the values
p² = 150² + 120² - (2)(150)(120) × Cos(25°)
p² = 22,500 + 14,400 - 36,000 × 0.9063
p² = 36,900 - 32,626.8
p² = 4,273.2
p = √4,273.2
p ≈ 65.4 m (nearest tenth)
QR = 65.4 m
Not really sure what exactly you are asking, but maybe a bar graph?
