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harina [27]
2 years ago
5

Listed below are the numbers of hurricanes that occurred in each year in a certain region. The data are listed in order by year.

Find the​ range, variance, and standard deviation for the given sample data. Include appropriate units in the results. What important feature of the data is not revealed by any of the measures of​ variation? 1010 1717 1010 1616 11 33 88 55 44 44 1717 55 88 1717 The range of the sample data is 1616 hurricanes.hurricanes. ​(Round to one decimal place as​ needed.) The standard deviation of the sample data is 5.55.5 hurricanes.hurricanes. ​(Round to one decimal place as​ needed.) The variance of the sample data is 30.330.3 hurricanes squared .hurricanes2. ​(Round to one decimal place as​ needed.) What important feature of the data is not revealed through the different measures of​ variation? A. The measures of variation do not reveal the difference between the largest number of hurricanes and the smallest number of hurricanes in the data. B. The measures of variation reveal nothing about how the numbers of hurricanes are spread. C. The measures of variation reveal nothing about the pattern over time. D. The measures of variation reveal no information about the scale of the data.
Mathematics
1 answer:
Schach [20]2 years ago
6 0

Answer: C. The measures of variation reveal nothing about the pattern over time.

Step-by-step explanation:

Given the following :

10 17 10 16 11 3 8 5 4 4 17 5 8 17

Range of hurricane data = 16

The standard deviation of sample data = 5.5 hurricanes

The variance of the sample data is 30.3 hurricane^2.

The measures of variation described above only shows the spread of the hurricane such as the range, that is the highest and lowest recorded.

The variance explains how spread out the data is and the standard deviation explains how values of a data differs from the mean value. The data fails to give time related information or pattern.

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Step-by-step explanation:

This is quite a doozy, my friend. We will set up a d = rt table, fill it in...and pray.

The table will look like this before we even fill anything in:

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We will put in the time difference of 25 minutes in just a sec.

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Since the times are the same (because they left at the same time, we will set the equations each equal to t. The distances are the same, too, I know that, but if we set the distances equal to each other and then solve the equations for a variable, the distances cancel each other out, leaving us with nowhere to go. Trust me, I tried that first! Didn't work.

Solving the first equation for time:

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