PLEASE HELP!! I will UPVOT

Melissa is standing 40 ft from a tree. The angle of elevation from where she is standing on the ground to the top of the tree is

bagirrra123 [75]

Tan(angle) = opposite length/ adjacent length

Tan(50) = h/40
h = 40 x tan(50)
h = 47.67 or 47.7 feet

3 0

3 years ago

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Help me with this please

mr Goodwill [35]

Answer:

You would choose Merry Berry Fruit Punch.

Step-by-step explanation:

We need to see the ration of fruit to water. To do this we need to divide the concentrate by the water.

Tropic Fresh Fruit Punch: 10/22 or 5/11

Merry Berry Fruit Punch: 6/13

We see that Tropic Fresh Fruit Punch has a ratio of 5/11 while Merry Berry Fruit Punch has a ratio of 6/13. When we have a common denominater, we can see the difference easier.

Tropic Fresh Fruit Punch: 65/143

Merry Berry Fruit Punch: 66/143

8 0

3 years ago

-2x-3=-x+6 plssssssss I can’t find a solution

Paladinen [302]

X=-9
Give specific name to solve it

3 0

3 years ago

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A school has 200 students and spends $40 on supplies for each student. The principal expects the number of students to increase

Xelga [282]

Answer:

$\mathbf{S(t)=200(\frac{105}{100})^{x}}$

$\mathbf{A(t)=40(\frac{98}{100})^{x}}$

$\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}$

Step-by-step explanation:

<h3>The predicted number of students over time, S(t) </h3>

Rate of increment is 5% per year.

A function 'S(t)' which gives the number of students in school after 't' years.

S(0) means the initial year when the number of students is 200.

S(0) = 200

S(1) means the number of students in school after one year when the number increased by 5% than previous year which is 200.

S(1) = 200 + 5% of 200 = $200+\frac{5}{100}\time200$ = $200(1+\frac{5}{100})$ = $200(\frac{105}{100})$

S(2) means the number of students in school after two year when the number increased by 5% than previous year which is S(1)

S(2) = S(1) + 5% of S(1) = $\textrm{S}(1)(\frac{105}{100})$ = $200(\frac{105}{100})(\frac{105}{100})$ = $200(\frac{105}{100})^{2}$

.

Similarly $\mathbf{S(x)=200(\frac{105}{100})^{x}}$

<h3>The predicted amount spent per student over time, A(t) </h3>

Rate of decrements is 2% per year.

A function 'A(t)' which gives the amount spend on each student in school after 't' years.

A(0) means the initial year when the number of students is 40.

A(0) = 40

A(1) means the amount spend on each student in school after one year when the amount decreased by 2% than previous year which is 40.

A(1) = 40 + 2% of 40 = $40-\frac{2}{100}\time40$ = $40(1-\frac{2}{100})$ = $40(\frac{98}{100})$

A(2) means the amount spend on each student in school after two year when the amount decreased by 2% than previous year which is A(1)

A(2) = A(1) + 2% of A(1) = $\textrm{A}(1)(\frac{98}{100})$ = $40(\frac{98}{100})(\frac{98}{100})$ = $40(\frac{98}{100})^{2}$

.

Similarly $\mathbf{A(x)=40(\frac{98}{100})^{x}}$

<h3>The predicted total expense for supplies each year over time, E(t)</h3>

Total expense = (number of students) × (amount spend on each student)

E(t) = S(t) × A(t)

$\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}$

$\mathbf{E(t)=8000(\frac{10290}{10000})^{x}}$

(NOTE : The value of x in all the above equation is between zero(0) to ten(10).)

6 0

3 years ago

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A rectangular picture frame has perimeter of 58 inches. The height of the frame is 18 inches. What is the width of the frame?

Stells [14]

Answer:

11 inches

Step-by-step explanation:

A rectangle's perimeter can be found using:

p=2l+2w

We know that the perimeter, p, is 58, and the length/height is 18. Therefore, we can substitute those values in

58=2(18)+2w

Multiply 2 and 18

58=36+2w

Since we want to find the width, we need to get w by itself. First, subtract 26 from both sides

58-36=36-36+2w

22=2w

Since w is being multiplied by 2, divide both sides by 2. This will cancel out the 2, and leave w by itself.

22/2=2w/2

11=w

So, the width is 11 inches

8 0

3 years ago