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Rudik [331]
3 years ago
8

Melissa is standing 40 ft from a tree. The angle of elevation from where she is standing on the ground to the top of the tree is

50°.
How tall is the tree?



Round the final answer to the nearest tenth.

Enter your answer in the box.

Mathematics
2 answers:
AysviL [449]3 years ago
6 0

Answer:

47.7\ ft

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In a right triangle the tangent of an angle is equal to divide the opposite side to the angle by the adjacent side to the angle

so

In this problem

tan(50\°)=\frac{BC}{AC}

The tall of the tree is BC

BC=ACtan(50\°)

AC=40\ ft

substitute

BC=40*tan(50\°)=47.7\ ft

bagirrra123 [75]3 years ago
3 0
Tan(angle) = opposite length/ adjacent length

Tan(50) = h/40
h = 40 x tan(50)
h = 47.67 or 47.7 feet
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The area of square is x^{2}+10 x+25 square units

<h3><u>Solution:</u></h3>

Given that square has side length (x+5) units

To find: area of square

<em><u>The area of square is given as:</u></em>

\text {Area of square }=\mathrm{a}^{2}

Where "a" is the length of side

From question, length of each side "a" = x + 5 units

Substituting the value in above formula,

\text {Area of square }=(x+5)^{2}

{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}

\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}

Thus the area of square is x^{2}+10 x+25 square units

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4 years ago
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8 0
3 years ago
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3 years ago
5(2t-3)-7.5t=0.5(12-t)
zmey [24]

Answer:

=10t-6-7.5t = 6-0.5t

= 2.5t- 6 = 6-0.5t

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larisa [96]

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since we know the <u>common difference</u> is d is 6, then to get from the 6th term to the 10th term, we use d 4 more times.

6th term..................37

7th term...................37 + 6

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9th term...................37 + 6 + 6 + 6

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7 0
3 years ago
Read 2 more answers
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