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3 years ago

if the diagonals of a quadrilateral biscects each other, then the quadrilateral is a parallelogram. true or false

Mathematics

2 answers:

Dima020 [189]3 years ago

8 0

Answer:

True.

Step-by-step explanation:

This is true for parallelograms - also for rectangles, rhombi and squares which are special types of parallelogram.

Irina-Kira [14]3 years ago

7 0

Answer:

true

Step-by-step explanation:

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Ksju [112]

Answer:

x = 20

Step-by-step explanation:

The 3 arcs UV, VW, WX form a semicircle, so sum to 180° , that is

4x + 2 + x + 78 = 180

5x + 80 = 180 ( subtract 80 from both sides )

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x = 20

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2 years ago

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Korvikt [17]

Answer: x= 9.5 hope this helps you

Step-by-step explanation:

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4 years ago

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deff fn [24]

Answer & Step-by-step explanation:

The problem says that the circles represents the sum of the two rectangles. So, in order to find the circle on the left side, we are going to have to add together (4x + 3y) and (2x - y).

(4x + 3y) + (2x - y)

4x + 3y + 2x - y

Combine like terms.

So, the answer for the circle on the left is 6x + 2y

Now, let's find the bottom right rectangle. To do so, we are going to subtract (x + 4y) from (4x + 5y).

(4x + 5y) - (x + 4y)

4x + 5y - x - 4y

Combine like terms.

So, the answer for the bottom right rectangle is 3x - y

Now, let's find the bottom circle. We can do this by adding together (3x - y) and (2x - y).

(3x - y) + (2x - y)

3x - y + 2x - y

Combine like terms.

So, the answer for the bottom circle is 5x - 2y

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3 years ago

Make M the subject <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bu%7D%7B%20%5Csqrt%7B2%20%7D%20%7D%20%20%3D%20%28%20%5Cfrac%

dimulka [17.4K]

Answer: $M=\frac{gu^2}{2}-N$

Work Shown:

$\frac{u}{\sqrt{2}} = \left(\frac{M+N}{g}\right)^{0.5}\\\\\\\left(\frac{M+N}{g}\right)^{0.5}=\frac{u}{\sqrt{2}}\\\\\\\sqrt{\frac{M+N}{g}}=\frac{u}{\sqrt{2}}\\\\\\\frac{M+N}{g}=\left(\frac{u}{\sqrt{2}}\right)^{2}\\\\\\\frac{M+N}{g}=\frac{u^2}{(\sqrt{2})^2}\\\\\\\frac{M+N}{g}=\frac{u^2}{2}\\\\\\M+N=\frac{gu^2}{2}\\\\\\M=\frac{gu^2}{2}-N\\\\\\$

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2 years ago