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3 years ago

Anyone have an idea?

Mathematics

2 answers:

Phantasy [73]3 years ago

7 0

Answer:

yes I have an idea jnhvhbvcf

choli [55]3 years ago

3 0

Answer: option C.) an 1.2 (n-1) -5 Sorry, no subscript for "a sub n"

Step-by-step explanation:

Substitute the values of n 1,2,3,4 and see if the output is the corresponding number in the sequence.

n = 1 2 3 4

-5 -3.8 -2.6 -1.4

an= 1.2 (n-1) -5 the n-1 needs to be a number multiplied by 1.2 produces a number added to -5 results in the number in the sequence.

a1=1.2(1-1) -5 a= 1.2(0) -5 a= -5

a2 1.2 (2-1) -5 a= 1.2(1) -5 a= -1.2 -5 a= -3.8

a3 1.2 (3-1) -5 a= 1.2(2) -5 a= -2.4 -5 a= -2.6

a4 1.2 (4-1) -5 a= 1.2(3) -5 a= -3.6 -5 a= -1.4

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What value of x is in the solution set of 3(x – 4) ≥ 5x + 2? –10 –5 5 10

emmasim [6.3K]

Answer:

The value of x is in the solution set of 3(x – 4) ≥ 5x + 2 is -10

Solution:

Need to determine which value of x from given option is solution set of 3(x – 4) ≥ 5x + 2

Lets first solve 3(x – 4) ≥ 5x + 2

3(x – 4) ≥ 5x + 2

=> 3x – 12 ≥ 5x + 2

=> 3x – 5x ≥ 12 + 2

=> -2x ≥ 14

=> -x ≥ 7

=> x ≤ -7

All the values of x which are less than or equal to -7 is solution set of 3(x – 4) ≥ 5x + 2. From given option there is only one value that is -10 which is less than -7

Hence from given option -10 is solution set of 3(x – 4) ≥ 5x + 2.

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3 years ago

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Vladimir [108]

Answer:

See below

Step-by-step explanation:

Q1. if a counting number is selected at random from a set of whole number less than or equal to 20 find the probability of getting:

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Whole numbers less than or equal to 20: $A\leq 20, A \subset \mathbb{Z}_{\ge 0} \\\implies A=\{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20\}$

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From the set A, the prime numbers are 2, 3, 5, 7, 11, 13, 17, 19.

Once we have 21 numbers in total and 8 prime numbers, the probability is:

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From the set A, the composite numbers are 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20.

Once we have 21 numbers in total and 11 composite numbers, the probability is:

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From the set A, the numbers divisible by three are 3, 6, 9, 12, 15, 18.

Once we have 21 numbers in total and 6 numbers divisible by three, the probability is:

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From the set A, the numbers square of 2 are 0, 1, 4, 9, 16.

$\sqrt{0} =0$

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$\sqrt{4} =2$

$\sqrt{9} =3$

$\sqrt{16} =4$

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igor_vitrenko [27]

Answer:

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Step-by-step explanation:

The ratio of money in bank:

Terry : Faye

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Terry put £220 in his account

Faye withdrew £300 from her account

Unknown:

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Solution:

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Solving this equation:

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