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2 years ago

Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.

Mathematics

1 answer:

Solnce55 [7]2 years ago

7 0

Answer:

7 digits can be used for each position

There are a total of 5 positions

N = 7^5 = 16,807 numbers

You have 7 choices for the first position, second position, etc.

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Quadrilateral ABCD is a rectangle. If AE = 36 and CE = 2x - 4, find x. B E А. D

krek1111 [17]

The value of the x is 20 if the quadrilateral ABCD is a rectangle and AE = 36 and CE = 2x - 4 because the diagonal of the rectangle bisect each other.

<h3>What is the area of the rectangle?</h3>

It is defined as the space occupied by the rectangle, which is planner 2-dimensional geometry.

The formula for finding the area of a rectangle is given by:

Area of rectangle = length × width

We know that the diagonal of the rectangle bisect each other.

AE = CE

36 = 2x - 4

2x = 40

x = 20

Thus, the value of the x is 20 if the quadrilateral ABCD is a rectangle and AE = 36 and CE = 2x - 4 because the diagonal of the rectangle bisect each other.

Learn more about the rectangle here:

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viktelen [127]

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3 years ago

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VashaNatasha [74]

Answer:

Step-by-step explanation:

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2 years ago

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What is the solution of √x-5 = x-11

PIT_PIT [208]

Hey!

To solve x in this equation we must first add five to both sides to get $\sqrt{x}$ on its own.

Original Equation :
$\sqrt{x} - 5 = x - 11$

New Equation {Added 5 to Both Sides} :
$\sqrt{x} =x-6$

Now we must square both sides of the equation.

Old Equation :
$\sqrt{x} =x-6$

New Equation {Changed by Squaring Both Sides} :
$x= x^{2} -12x+36$

And now we must solve the new equation.

Step 1 - Switch sides
$x^{2} -12x+36=x$

Step 2 - Subtract x from both sides
$x^{2} -12x+36-x=x-x$

Step 3 - Simplify
$x^{2} -13x+36=0$

Now we need to solve the rest of the equation using the quadratic formula.

$\frac{-(-13)+ \sqrt{(-13) ^{2}-4*1*36 } }{2*1}$

${13+ \sqrt{(-13)^{2}-4*1*36 }=13+ \sqrt{25}$

$\frac{13+ \sqrt{25}}{2}$

$\sqrt{25}=5$

$\frac{13+5}{2}$

$\frac{18}{2}$

9

$\frac{-(-13)- \sqrt{(-13) ^{2} -4*1*36} }{2*1}$

4

So, this means that in the equation $\sqrt{x} -5=x-11$ , x = 9 and x = 4.

Hope this helps!

- Lindsey Frazier ♥

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A bag contains 4 red marbles, 5 yellow marbles, and 6 blue marbles. three marbles are to be picked out randomly (without replace

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