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3 years ago

Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.

Mathematics

1 answer:

Solnce55 [7]3 years ago

7 0

Answer:

7 digits can be used for each position

There are a total of 5 positions

N = 7^5 = 16,807 numbers

You have 7 choices for the first position, second position, etc.

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I really don't get the whole Mean, Median and Mode thing.

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Phantasy [73]

What are you trying to solve for?

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