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tester [92]
3 years ago
10

Which expression is equivalent to -2 - 7 -2 - (-7) 2 - 7 -2 + (-7) 2+7

Mathematics
2 answers:
andrew11 [14]3 years ago
8 0

Answer:

-2+ (-7) = -2 - 7

Step-by-step explanation:

Lunna [17]3 years ago
7 0

Answer:

Step-by-step explanation:

-2+ (-7) = -2 - 7

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Which expression is equivalent to (4x+11)+7x?
Anna007 [38]
HEY THERE FAM.

THE CORRECT ANSWER IS....<span> D.(4x-7x)+11</span>
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Which bear describes the relationship between the successive terms in the sequence shown
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Evaluate 32 divided by 2^3 + 12
matrenka [14]

Answer: 8/5

Step-by-step explanation:

2^3 = 2*2*2 = 8

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= 32/20

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4 0
2 years ago
Read 2 more answers
Consider a triangle ABC like the one below. Suppose that a = 31, b = 23, and c = 20. (The figure is not drawn to scale.) Solve t
krok68 [10]

The solution to the triangle is A = 92.0, B = 47.9 and C = 40.1

<h3>How to solve the triangle?</h3>

The figure is not given;

However, the question can still be solved without it

The given parameters are:

a = 31, b = 23, and c = 20

Calculate angle A using the following law of cosine

a² = b² + c² - 2bc * cos(A)

So, we have:

31² = 23² + 20² - 2 * 23 * 20 * cos(A)

Evaluate

961 = 929 - 920 * cos(A)

Subtract 929 from both sides

32 =- 920 * cos(A)

Divide both sides by -920

cos(A) = -0.0348

Take the arc cos of both sides

A = 92.0

Calculate angle B using the following law of sine

a/sin(A) = b/sin(B)

So, we have:

31/sin(92) = 23/sin(B)

This gives

31.0189 = 23/sin(B)

Rewrite as:

sin(B) =23/31.0189

Evaluate

sin(B) =0.7415

Take arc sin of both sides

B = 47.9

Calculate angle C using:

C = 180 - 92.0 - 47.9

Evaluate

C = 40.1

Hence, the solution to the triangle is A = 92.0, B = 47.9 and C = 40.1

Read more about triangles at:

brainly.com/question/2217700

#SPJ1

6 0
2 years ago
F(x)=1/4x^2+1/2x-35/4 how do I factor fractions?
Ivanshal [37]

let's multiply both sides by the LCD of all fractions, in this case is 4, just to do away with the denominators for a few seconds

\bf f(x) = \cfrac{1}{4}x^2+\cfrac{1}{2}x-\cfrac{35}{4}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{4}}{4[f(x)]=4\left( \cfrac{1}{4}x^2+\cfrac{1}{2}x-\cfrac{35}{4} \right)} \\\\\\ 4f(x) = x^2+2x-35\implies 4f(x) = (x+7)(x-5) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill f(x) = \cfrac{1}{4}(x+7)(x-5)~\hfill

5 0
3 years ago
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