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3 years ago

The sum of four consecutive whole numbers is 94.what is the largest numbers?

Mathematics

1 answer:

tekilochka [14]3 years ago

7 0

Answer: 25

Step-by-step explanation: This problem states that the sum of four consecutive whole numbers is 94 and it asks us to find the largest number.

Three consecutive whole numbers can be represented as followed.

X ⇒ first number

X + 1 ⇒ second number

X + 2 ⇒ third number

X + 3 ⇒ fourth number

Since the sum of our four consecutive whole numbers is 94, we can set up an equation to represent this.

X + X + 1 + X + 2 + X + 3 = 94

We can combine the x's on the left side of the equation and combine the numbers as well.

4x + 6 = 94

-6 -6 ← subtract 6 from both sides of the equation

4x = 88

÷4 ÷4

X = 22

X ⇒ first number = 22

X + 1 ⇒ second number = 23

X + 2 ⇒ third number = 24

X + 3 ⇒ fourth number = 25

Therefore, the largest number would be 25.

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Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- see attachment for the generated data

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

PLEASE HURRYYYYYY

BlackZzzverrR [31]

C) r = T + 25.3 because you isolate the r variable

8 0

3 years ago

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Carson and Jayden kept track of how many miles they ran during one week. Carson ran a total of 43 miles, which was 12 miles more

kozerog [31]

Answer:

Step-by-step explanation:

So the answer is 31 because

Carson ran 43

Jayden ran 12 miles less

so subtract 43-12=31

7 0

3 years ago

Read 2 more answers

Least to greatest 2/9, 21%, 0.21, 11/50

miv72 [106K]

2/9=22%
21%
21%
22%

So it would be 21%, 0.21, 11/50, 2/9.

4 0

3 years ago

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Joe can clear a lot in 2.5 hours. His partner can do the same job in 7.5 hours. How long will it take them working together?

irina [24]

Answer:

The time required by both persons to complete the work T = 1.458 hours

Step-by-step explanation:

Given data

Time required by Joe to clear a lot $T_1$ = 2.5 hours

Time required by his partner to clear a lot $T_2$ = 2.5 hours

Time required by both persons to complete the work by working together

$T = \frac{T_1 T_2}{T_1 + T_2}$

$T = \frac{(2.5)(3.5)}{2.5 + 3.5}$

T = 1.458 hours

Therefore the time required by both persons to complete the work T = 1.458 hours

7 0

3 years ago