The heat of a chemical reaction (change of enthalý) may be calcualted as the heat of formation of the products less the heat of formation of the reactants.
Then, for the given equation, the total heat of the combustion of pentnae is:
<span>ΔH°f = 5* ΔH°f CO2(g) + 6ΔH°f H2O(g) - ΔH°f C5H12(g) - 8ΔH°f O2(g)
</span>The standard heat of formation of O2(g) is zero because that is its natural state.
Now you can replace in the equation the values given:
<span>ΔH° = 5*(-393.5 kJ/mol) + 6*(-241.8kj/mol) - (-35.1kJ/mol) - 0
ΔH° = -3,383.2 kJ/mol
</span>
Then, the heat of the combustion of pentane is -3,383.2 kj/mol
Answer:
Explanation:
I just had this question on my test
When a candle burns, it will change oxygen to carbon dioxide. when we put a glass jar over it,
the candle will burn till no more oxygen is left so after a while, it will stop burning