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2 years ago

If the DISTANCE traveled for the PURPLE line is 3.5m and it traveled for 1.75 seconds, what was it's speed?

Chemistry

2 answers:

pochemuha2 years ago

7 0

Answer:

speed = 2 meters per second

= 2 m/s

Explanation:

julia-pushkina [17]2 years ago

4 0

Answer:0.5 m/s

Explanation: Divide D: distance To L: line 3.5 divided by 1.75 gives you 0.5 m/s

distance/time

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Which of the following does NOT involve a physical change?

jasenka [17]

Answer:mixing decomposing

Explanation:

Melting and grinding changes the physical form and mixing decomposing doesn’t

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3 years ago

Find the density if the volume is 15 mL and the mass is 8.6 g. (5 pts)

allsm [11]

Answer:

$\large \boxed{\text{0.57 g/mL; 3.7 mL; 6.6 g; 0.366 g/mL}}$

Explanation:

1. Density from mass and volume

$\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\rho = \dfrac{m}{V}\\\\\rho = \dfrac{\text{8.6 g}}{\text{15 mL}} = \text{0.57 g/mL}\\\text{The density is $\large \boxed{\textbf{0.57 g/mL}}$}$

2. Volume from density and mass

$V = \text{9.7 g}\times\dfrac{\text{1 mL}}{\text{2.6 g}} = \text{3.7 mL}\\\\\text{The volume is $\large \boxed{\textbf{3.7 mL}}$}$

3. Mass from density and volume

$\text{Mass} = \text{4.1 cm}^{3} \times \dfrac{\text{1.6 g}}{\text{1 cm}^{3}} = \textbf{6.6 g}\\\\\text{The mass is $\large \boxed{\textbf{6.6 g}}$}$

4. Density by displacement

Volume of water + object = 24.6 mL

Volume of water =<u> 12.8 mL</u>

Volume of object = 11.8 mL

$\rho = \dfrac{\text{4.3 g}}{\text{11.8 mL}} = \text{0.36 g/mL}\\\text{The density is $\large \boxed{\textbf{0.36 g/mL}}$}$

Your drawing showing water displacement using a graduated cylinder should resemble the figure below.

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3 years ago

Many people are proponents of using nuclear power instead of burning coal to generate electricity. What is an environmental adva

nirvana33 [79]

Answer:

C) Less carbon dioxide would be released into the atmosphere.

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3 years ago

Read 2 more answers

i have an unknown volume of gas at a pressure of 0.50 atm a temperature of 325 k. If i raise the pressure to 1.2 atm, decrease t

Ronch [10]

Assuming that the number of mols are constant for both conditions:
$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$
Now you plug in the given values. V_1 is the unknown.
$\frac{0.50 atm*V_1}{325K} = \frac{1.2 atm* 48 L}{230K}
$
Separate V_1
$V_1= \frac{1.2 atm* 48 L * 325K }{230K*0.50 atm }$
V= 162.782608696 L

There are 2 sig figs

V= 160 L

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3 years ago

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Cell membrane is the answer.

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