The person on top might be a scam seen the same url too many times. J
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Answer:
Step-by-step explanation:
It can be helpful to actually see the graph. For 0 ≤ θ ≤ π, a circle is developed above the x-axis, symmetrical about the y-axis (θ=π/2). For π ≤ θ ≤ 2π, the same circle is traced again in the same direction (CCW), as values of r are negative for those angles.
The circle has a radius of 2.5, centered at (0, 2.5), so the diameter is 5 units. The length of the diameter is the farthest distance between any two points on a circle.
Answer:
The value of g(22) = 31
Hence, option D is correct.
Step-by-step explanation:
Given
To determine
g(f(2)) = ?
To determine g(f(2)), first, we need to calculate f(2)
so substitute x = 2 in f(x)= 4x³ – 10
f(x)= 4x³ – 10
f(2) = 4(2)³ - 10
f(2) = 32 - 10
f(2) = 22
so
g(f(2)) = g(22)
now substitute x = 22 in g(x) = [3x - 4] / [2]
g(x) = [3x - 4] / [2]
g(22) = [3(22) - 4] / [2]
g(22) = [66-4] / [2]
g(22) = [62] / [2]
g(22) = 31
so
g(f(2)) = g(22) = 31
Therefore, the value of g(22) = 31
Hence, option D is correct.
Answer: m∠W = 56
because UVWX is a rhombus
=> UV // WX
=> 2y + 2y - 68 = 180
<=> 4y = 248
<=> y = 62
=> m∠W = 2.62 - 68 = 56
Step-by-step explanation:
