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Kryger [21]
2 years ago
14

I need help please help

Mathematics
2 answers:
almond37 [142]2 years ago
7 0

Answer:

first one

28.26 im not 100% correct i dont think

Artemon [7]2 years ago
5 0
It’s the first one.
i think it’s the first one
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Can anyone please help me with this?
marin [14]

Answer:

I believe that It would be b

4 0
2 years ago
What is 3a+2c=26 solve for a and c
blondinia [14]

Simplifying

3a + 2b + c = 26

Solving

3a + 2b + c = 26

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2b' to each side of the equation.

3a + 2b + -2b + c = 26 + -2b

Combine like terms: 2b + -2b = 0

3a + 0 + c = 26 + -2b

3a + c = 26 + -2b

Add '-1c' to each side of the equation.

3a + c + -1c = 26 + -2b + -1c

Combine like terms: c + -1c = 0

3a + 0 = 26 + -2b + -1c

3a = 26 + -2b + -1c

Divide each side by '3'.

a = 8.666666667 + -0.6666666667b + -0.3333333333c

Simplifying

a = 8.666666667 + -0.6666666667b + -0.3333333333c

3 0
3 years ago
Read 2 more answers
A “stick” object of height 10 cm is standing in front of a point X–ray source at a distance of 50 cm from the source. The detect
blagie [28]

Answer:

40 cm.

Step-by-step explanation:

Given,

height of the object = 10 cm

Distance of the object from the X-ray= 50 cm

Distance of detector from the source = 2 m = 200 cm

Height of the image, h = ?

Now,

\tan \theta = \frac{P}{B}

\tan \theta = \frac{10}{50}

\tan \theta = \frac{1}{5}

Again applying

\tan \theta = \frac{P}{B}

\frac{1}{5} = \frac{h}{200}

h = 40 cm

Hence, height of the image is equal to 40 cm.

6 0
3 years ago
A square has an area of 289 sq cm. what is the length of one side
MatroZZZ [7]
For this problem you can do it one of two ways. The first way would be simply take the square root because the area of a square is one side squared. The other way using the same rule would be to go up from a reasonable number and square it, if that is not the number you are looking for add 1 to the original number and square it again. if you cannot square and square root in your head, you should be allowed to use a calculator to get the answer or 17 as the length of a side.
5 0
3 years ago
How do you simplify Radicals?<br>√180v^4​
julsineya [31]

Here are the steps required for Simplifying Radicals:

Step 1: Find the prime factorization of the number inside the radical. Start by dividing the number by the first prime number 2 and continue dividing by 2 until you get a decimal or remainder. Then divide by 3, 5, 7, etc. until the only numbers left are prime numbers. Also factor any variables inside the radical.

Step 2: Determine the index of the radical. The index tells you how many of a kind you need to put together to be able to move that number or variable from inside the radical to outside the radical. For example, if the index is 2 (a square root), then you need two of a kind to move from inside the radical to outside the radical. If the index is 3 (a cube root), then you need three of a kind to move from inside the radical to outside the radical.

Step 3: Move each group of numbers or variables from inside the radical to outside the radical. If there are nor enough numbers or variables to make a group of two, three, or whatever is needed, then leave those numbers or variables inside the radical. Notice that each group of numbers or variables gets written once when they move outside the radical because they are now one group.

Step 4: Simplify the expressions both inside and outside the radical by multiplying. Multiply all numbers and variables inside the radical together. Multiply all numbers and variables outside the radical together.

Shorter version:

Step 1: Find the prime factorization of the number inside the radical.  

Step 2: Determine the index of the radical. In this case, the index is two because it is a square root, which means we need two of a kind.  

Step 3: Move each group of numbers or variables from inside the radical to outside the radical. In this case, the pair of 2’s and 3’s moved outside the radical.  

Step 4: Simplify the expressions both inside and outside the radical by multiplying.

7 0
3 years ago
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